Let the EMF of the cell be E and internal resistance be r. Using Ohm’s law:For 2Ω resistor: E = 0.9 (2 + r) For 7 resistor E = 0.3 (7 + r) Equating both: 0.9(2 + r) = 0.3 ...
Discussion Forum Latest Questions
Class 9 Maths Chapter 11, Surface Areas and Volumes, focuses on calculating the surface areas and volumes of various 3D shapes like cubes, cuboids, cylinders, cones, spheres and hemispheres. Students can practice MCQs with answers to master concepts like the ...
Dive into the captivating world of Symmetry with Class 6 Maths Chapter 9, where students explore the beauty of balance and proportion in shapes and patterns. Engage with MCQs with answers to strengthen your understanding of concepts like lines of ...
In a potentiometer, the balancing length is proportional to the emf of the cell. Given V balances at l/3, for a cell of emf 1.5V, the new balancing length is (1.5V/V) × (l/3) = 2l/3. Answer: (d) 2l/3. Class 12th ...
For balance in a Wheatstone bridge: P/Q = Rshunted/Seffective Solving for R_shunted, we get 2Ω. Correct answer: (b) 2Ω. Class 12th Science Physics NCERT MCQ Questions NCERT Books MCQ Questions Session 2024-2025.