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Sanjay01 Kumar

The fuse current (I) is proportional to the square root of the cross-sectional area. Since area is proportional to the square of the radius, doubling the radius increases I by √4 = 2, giving = 5 × 2¹.5 = 14.7 ...

Kawal jeet Singh

Resistance of a wire is given by R = ρ L/A . When stretched, L ′ = 1.5L and = A/(1.5)², so new resistance: R ′ = ρ 1.5L/A/(1.5)² = 2.25R To make R′ = 4R, solving gives fraction 1/6. ...