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  1. Let the side length of the cube be a. The volume of the cube is given by V = a³, which means that a = V¹ᐟ³. The total surface area of the cube is given by S = 6a². Substituting the expression for a into the surface area formula gives S = 6(V¹ᐟ³)² = 6V²ᐟ³. Thus, S = 6∛(V²).   For more NCERT SoluRead more

    Let the side length of the cube be a. The volume of the cube is given by V = a³, which means that a = V¹ᐟ³. The total surface area of the cube is given by S = 6a². Substituting the expression for a into the surface area formula gives S = 6(V¹ᐟ³)² = 6V²ᐟ³. Thus, S = 6∛(V²).

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/

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  2. Let the side length of the cube be a. The total surface area is given by the formula S = 6a². Solving for the side length a gives a² = S/6, so a = √(S/6) = (S/6)¹ᐟ². The volume of the cube is V = a³. Substituting a gives V = ((S/6)¹ᐟ²)³ = (S/6)³ᐟ² = S√S/(6√6).   For more NCERT Solutions of ClasRead more

    Let the side length of the cube be a. The total surface area is given by the formula S = 6a². Solving for the side length a gives a² = S/6, so a = √(S/6) = (S/6)¹ᐟ². The volume of the cube is V = a³. Substituting a gives V = ((S/6)¹ᐟ²)³ = (S/6)³ᐟ² = S√S/(6√6).

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/

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    • 97
  3. The required rise in the water level is h = 20 cm − 16 cm = 4 cm. The cylindrical volume corresponding to this rise is V = πr²h = π × 4² × 4 = 64π cm³. Each marble is a sphere of radius 1 cm, with volume v = (4/3)π(1)³ = (4/3)π cm³. Dividing the required volume by one marble's volume gives 64π / [(4Read more

    The required rise in the water level is h = 20 cm − 16 cm = 4 cm. The cylindrical volume corresponding to this rise is V = πr²h = π × 4² × 4 = 64π cm³. Each marble is a sphere of radius 1 cm, with volume v = (4/3)π(1)³ = (4/3)π cm³. Dividing the required volume by one marble’s volume gives 64π / [(4/3)π] = 64 × (3/4) = 48 marbles.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/

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    • 99
  4. Indigenous and forest-dwelling communities protect forest biodiversity through time-tested traditional knowledge and ecological ethics. They designate virgin forest tracts as sacred groves (sarnas or devarakadus), completely barring logging and hunting. By practicing rotational foraging, protectingRead more

    Indigenous and forest-dwelling communities protect forest biodiversity through time-tested traditional knowledge and ecological ethics. They designate virgin forest tracts as sacred groves (sarnas or devarakadus), completely barring logging and hunting. By practicing rotational foraging, protecting keystone species like Mahua and Peepal, guarding boundaries against illegal loggers and clearing dry leaf litter, they maintain soil health, protect wildlife habitats and prevent large-scale wildfire outbreaks.

     

    For more NCERT Solutions of Class 9 Social Science Part 2 Chapter 2 Life on Earth Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/part-2-chapter-2/

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    • 89
  5. A forest fire is an uncontrolled blaze spreading through forests, brushland or grasslands, fueled by dry combustible biomass, wind and heat. Below is an operational plan for prevention and mitigation: Prevention Plan (Before Outbreak) Maintain cleared fire lines to physically separate forest blocksRead more

    A forest fire is an uncontrolled blaze spreading through forests, brushland or grasslands, fueled by dry combustible biomass, wind and heat. Below is an operational plan for prevention and mitigation:

    Prevention Plan (Before Outbreak)

    • Maintain cleared fire lines to physically separate forest blocks and stop advancing flames.
    • Conduct controlled early burning of dry leaf litter and undergrowth before peak summer.
    • Impose strict bans on unextinguished campfires, discarded matches and unchecked agricultural residue burning near forest borders.
    • Train Joint Forest Management (JFM) village committees and run awareness campaigns.

    Mitigation Plan (During & After Outbreak)

    • Track real-time thermal anomalies using satellite systems (such as FSI-MODIS/SNPP-VIIRS) and forest watchtowers for immediate alerting.
    • Deploy rapid response strike teams equipped with pressurized backpack sprayers, beaters and spark arrestors.
    • Construct temporary counter-fires and douse hotspots to prevent fire reignition.
    • Replant native fire-hardy flora and restore affected topsoil and watershed zones.

     

    For more NCERT Solutions of Class 9 Social Science Part 2 Chapter 2 Life on Earth Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/part-2-chapter-2/

     

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