Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
We want to connect the people who have knowledge to the people who need it, to bring together people with different perspectives so they can understand each other better, and to empower everyone to share their knowledge.
Given a cube with volume V, express its total surface area S in terms of V.
Let the side length of the cube be a. The volume of the cube is given by V = a³, which means that a = V¹ᐟ³. The total surface area of the cube is given by S = 6a². Substituting the expression for a into the surface area formula gives S = 6(V¹ᐟ³)² = 6V²ᐟ³. Thus, S = 6∛(V²). For more NCERT SoluRead more
Let the side length of the cube be a. The volume of the cube is given by V = a³, which means that a = V¹ᐟ³. The total surface area of the cube is given by S = 6a². Substituting the expression for a into the surface area formula gives S = 6(V¹ᐟ³)² = 6V²ᐟ³. Thus, S = 6∛(V²).
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessGiven a cube with total surface area S, express its volume V in terms of S.
Let the side length of the cube be a. The total surface area is given by the formula S = 6a². Solving for the side length a gives a² = S/6, so a = √(S/6) = (S/6)¹ᐟ². The volume of the cube is V = a³. Substituting a gives V = ((S/6)¹ᐟ²)³ = (S/6)³ᐟ² = S√S/(6√6). For more NCERT Solutions of ClasRead more
Let the side length of the cube be a. The total surface area is given by the formula S = 6a². Solving for the side length a gives a² = S/6, so a = √(S/6) = (S/6)¹ᐟ². The volume of the cube is V = a³. Substituting a gives V = ((S/6)¹ᐟ²)³ = (S/6)³ᐟ² = S√S/(6√6).
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessA cylindrical glass of height 25 cm and radius 4 cm has water up to a height of 16 cm. A crow wants to drink water from this glass. The water must be at a height of 20 cm for the crow to reach it. There are some marbles lying around. How many marbles of radius 1 cm should the crow drop into the glass to make the water reach the required height?
The required rise in the water level is h = 20 cm − 16 cm = 4 cm. The cylindrical volume corresponding to this rise is V = πr²h = π × 4² × 4 = 64π cm³. Each marble is a sphere of radius 1 cm, with volume v = (4/3)π(1)³ = (4/3)π cm³. Dividing the required volume by one marble's volume gives 64π / [(4Read more
The required rise in the water level is h = 20 cm − 16 cm = 4 cm. The cylindrical volume corresponding to this rise is V = πr²h = π × 4² × 4 = 64π cm³. Each marble is a sphere of radius 1 cm, with volume v = (4/3)π(1)³ = (4/3)π cm³. Dividing the required volume by one marble’s volume gives 64π / [(4/3)π] = 64 × (3/4) = 48 marbles.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/
See lessHow do forest dwellers contribute to the protection and conservation of forests?
Indigenous and forest-dwelling communities protect forest biodiversity through time-tested traditional knowledge and ecological ethics. They designate virgin forest tracts as sacred groves (sarnas or devarakadus), completely barring logging and hunting. By practicing rotational foraging, protectingRead more
Indigenous and forest-dwelling communities protect forest biodiversity through time-tested traditional knowledge and ecological ethics. They designate virgin forest tracts as sacred groves (sarnas or devarakadus), completely barring logging and hunting. By practicing rotational foraging, protecting keystone species like Mahua and Peepal, guarding boundaries against illegal loggers and clearing dry leaf litter, they maintain soil health, protect wildlife habitats and prevent large-scale wildfire outbreaks.
For more NCERT Solutions of Class 9 Social Science Part 2 Chapter 2 Life on Earth Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/part-2-chapter-2/
See lessWhat is a forest fire? Prepare a plan for prevention and mitigation of forest fires.
A forest fire is an uncontrolled blaze spreading through forests, brushland or grasslands, fueled by dry combustible biomass, wind and heat. Below is an operational plan for prevention and mitigation: Prevention Plan (Before Outbreak) Maintain cleared fire lines to physically separate forest blocksRead more
A forest fire is an uncontrolled blaze spreading through forests, brushland or grasslands, fueled by dry combustible biomass, wind and heat. Below is an operational plan for prevention and mitigation:
Prevention Plan (Before Outbreak)
Mitigation Plan (During & After Outbreak)
For more NCERT Solutions of Class 9 Social Science Part 2 Chapter 2 Life on Earth Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/part-2-chapter-2/
See less