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What are the jump sizes that will reach both treasures at 14 and 36?
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump tRead more
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump that aligns perfectly with both treasures.
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Find all multiples of 40 that lie between 310 and 410.
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360Read more
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360, and 400, as all are divisible by 40 and fall within the specified range.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
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Who am I? a) I am a number less than 40. One of my factors is 7. The sum of my digits is 8.
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer iRead more
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer is 35, fulfilling all the stated conditions.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
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Who am I? b) I am a number less than 100. Two of my factors are 3 and 5. One of my digits is 1 more than the other.
To solve, the number must be under 100, divisible by both 3 and 5, and its digits differ by 1. Numbers divisible by 3 and 5 have 15 as their least common multiple. Checking these, 15 fits perfectly, as its digits (1 and 5) meet the condition where one is exactly 1 more than the other. The factors ofRead more
To solve, the number must be under 100, divisible by both 3 and 5, and its digits differ by 1. Numbers divisible by 3 and 5 have 15 as their least common multiple. Checking these, 15 fits perfectly, as its digits (1 and 5) meet the condition where one is exactly 1 more than the other. The factors of 15 include 1, 3, 5, and 15, further verifying it meets all the criteria.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
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Find the common factors of: a) 20 and 28
To determine the common factors of 20 and 28, list their factors. For 20, the factors are 1, 2, 4, 5, 10, and 20. For 28, the factors are 1, 2, 4, 7, 14, and 28. Comparing these, the common factors are 1, 2, and 4. These shared divisors show the numbers' overlap, with 4 being the greatest common divRead more
To determine the common factors of 20 and 28, list their factors. For 20, the factors are 1, 2, 4, 5, 10, and 20. For 28, the factors are 1, 2, 4, 7, 14, and 28. Comparing these, the common factors are 1, 2, and 4. These shared divisors show the numbers’ overlap, with 4 being the greatest common divisor (GCD) and thus the largest number that divides both evenly.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
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