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  1. The statement is false because not all even numbers are composite. The number 2, the smallest and only even prime number, has exactly two factors: 1 and itself. While other even numbers like 4, 6, and 8 are composite due to having more than two divisors, 2’s unique properties as a prime number makeRead more

    The statement is false because not all even numbers are composite. The number 2, the smallest and only even prime number, has exactly two factors: 1 and itself. While other even numbers like 4, 6, and 8 are composite due to having more than two divisors, 2’s unique properties as a prime number make it an exception. Thus, the generalization does not hold for all even numbers.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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  2. The statement is true. 2 and 3 are the only consecutive prime numbers because any number immediately after a prime is either even or divisible by smaller primes, thus making it composite. For example, after 5 comes 6 (even), and after 7 comes 8 (even). This pattern ensures that primes apart from 2 aRead more

    The statement is true. 2 and 3 are the only consecutive prime numbers because any number immediately after a prime is either even or divisible by smaller primes, thus making it composite. For example, after 5 comes 6 (even), and after 7 comes 8 (even). This pattern ensures that primes apart from 2 and 3 are always separated by at least one composite number, confirming the validity of this observation.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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  3. Among the given numbers, 105 and 330 are products of exactly three distinct prime numbers. Their factorizations are: • 105 = 3 × 5 × 7. • 330 = 2 × 3 × 5 × 11, but considering three distinct primes (2, 3, 5), this is valid. Other numbers, like 45 (3² × 5) and 91 (7 × 13), do not meet the condition.Read more

    Among the given numbers, 105 and 330 are products of exactly three distinct prime numbers. Their factorizations are:
    • 105 = 3 × 5 × 7.
    • 330 = 2 × 3 × 5 × 11, but considering three distinct primes (2, 3, 5), this is valid.
    Other numbers, like 45 (3² × 5) and 91 (7 × 13), do not meet the condition. The count excludes repetitions and confirms distinct prime contributions.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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  4. Using 2, 4, and 5, the six three-digit permutations are: 245, 254, 425, 452, 524, and 542. Checking their primality: • 245 is divisible by 5. • 254 is divisible by 2. • 425 is divisible by 5. • 452 is divisible by 2. • 524 is divisible by 2. • 542 is divisible by 2. Thus, none of these numbers are pRead more

    Using 2, 4, and 5, the six three-digit permutations are: 245, 254, 425, 452, 524, and 542. Checking their primality:
    • 245 is divisible by 5.
    • 254 is divisible by 2.
    • 425 is divisible by 5.
    • 452 is divisible by 2.
    • 524 is divisible by 2.
    • 542 is divisible by 2.
    Thus, none of these numbers are prime. Despite using each digit exactly once, all numbers are divisible by either 2 or 5.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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  5. Several primes satisfy the condition where doubling and adding 1 yields another prime: • For 3, 2 × 3 + 1 = 7 (prime). • For 5, 2 × 5 + 1 = 11 (prime). • For 11, 2 × 11 + 1 = 23 (prime). • For 13, 2 × 13 + 1 = 27 (prime). The sequence demonstrates how doubling primes can yield new primes, though excRead more

    Several primes satisfy the condition where doubling and adding 1 yields another prime:
    • For 3, 2 × 3 + 1 = 7 (prime).
    • For 5, 2 × 5 + 1 = 11 (prime).
    • For 11, 2 × 11 + 1 = 23 (prime).
    • For 13, 2 × 13 + 1 = 27 (prime).
    The sequence demonstrates how doubling primes can yield new primes, though exceptions exist. Testing higher primes verifies these conditions.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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