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To which part of the electromegnetic spectrum does the wave of frequency 5 × 10¹⁹ Hz belong?
A wave with a frequency of 5 × 10¹⁹ Hz belongs to the X-rays region of the electromagnetic spectrum, characterized by extremely high energy and frequency, used in medical treatments and scientific research. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-8Read more
A wave with a frequency of 5 × 10¹⁹ Hz belongs to the X-rays region of the electromagnetic spectrum, characterized by extremely high energy and frequency, used in medical treatments and scientific research.
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Arrange the given electromagnetic radiations in the descending order of wavelengths: X-rays, rsdio waves, blue light, infrared light.
The descending order of wavelengths for the given electromagnetic radiations is: Radio waves > Infrared light > Blue light > X-rays. Radio waves have the longest wavelengths, while X-rays have the shortest. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/Read more
The descending order of wavelengths for the given electromagnetic radiations is:
Radio waves > Infrared light > Blue light > X-rays.
Radio waves have the longest wavelengths, while X-rays have the shortest.
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The distance of two planets from the sun are 10¹³ m and 10¹² m respectively. The ratio of time periods of the planets is
The time period of a planet's revolution around the Sun is governed by Kepler's Third Law, which establishes a relationship between the orbital period and the distance of the planet from the Sun. According to this law, the square of the orbital period of a planet is proportional to the cube of its aRead more
The time period of a planet’s revolution around the Sun is governed by Kepler’s Third Law, which establishes a relationship between the orbital period and the distance of the planet from the Sun. According to this law, the square of the orbital period of a planet is proportional to the cube of its average distance from the Sun. This means that as the distance of a planet from the Sun increases, its orbital period becomes significantly longer.
In this scenario, the distances of two planets from the Sun are 10¹³ meters and 10¹² meters, respectively. The ratio of their orbital periods can be determined using Kepler’s Third Law. For the first planet, which is farther from the Sun, the time period increases because the gravitational pull decreases with distance, resulting in a slower orbital speed.
Using the law, it is found that the ratio of the time periods of the two planets is 10√10. This value shows that the first planet, being ten times farther from the Sun, takes considerably longer to complete one revolution than the second planet. This result demonstrates the profound effect of distance on the orbital dynamics of celestial bodies in a solar system.
See lessA body of mass m is placed on earth surface which is taken from earth surface to a height of h = 3 R. Then change in gravitational
When a body of mass m is moved from the surface of the Earth to a height equal to three times the Earth's radius h = 3R, there is a change in its gravitational potential energy. Gravitational potential energy depends on the position of the body relative to the center of the Earth and decreases as thRead more
When a body of mass m is moved from the surface of the Earth to a height equal to three times the Earth’s radius h = 3R, there is a change in its gravitational potential energy. Gravitational potential energy depends on the position of the body relative to the center of the Earth and decreases as the distance from the center increases.
At the surface of the Earth, the body’s potential energy is determined by the distance R from the center. When the body is taken to a height of h = 3R, the total distance from the Earth’s center becomes 4R. The gravitational potential energy at these two points differs because potential energy is inversely proportional to the distance from the center of the Earth.
The change in gravitational potential energy is calculated as the difference between the potential energy at the surface and at the height h = 3R. After simplifying the relationship, it is found that the change in potential energy is mgR/4.
This result reflects how gravitational potential energy decreases with increasing distance from the center of the Earth. It also demonstrates the significance of height and mass in calculating energy changes during such movements, essential in space travel and satellite deployment.
See lessIdentify the part of the electromagnetic spectrum used i (i) radar and (ii) eye surgery. Write their frequency range.
(i) Radar uses microwaves, part of the electromagnetic spectrum with frequencies ranging from 1 GHz to 300 GHz. (ii) Eye surgery employs ultraviolet (UV) light, specifically excimer lasers, with frequencies ranging from 750 THz to 30,000 THz. For more visit here: https://www.tiwariacademy.com/ncert-Read more
(i) Radar uses microwaves, part of the electromagnetic spectrum with frequencies ranging from 1 GHz to 300 GHz.
(ii) Eye surgery employs ultraviolet (UV) light, specifically excimer lasers, with frequencies ranging from 750 THz to 30,000 THz.
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