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What is an example of mensuration for Class 6?
A common Class 6 mensuration example is calculating the area and perimeter of a rectangular park. For instance, if the park's length is 20 m and its breadth is 15 m: • Area (space enclosed): length x breadth = 20 x 15 = 300 square meters. • Perimeter (boundary length): 2 x (length + breadth) = 2 x (Read more
A common Class 6 mensuration example is calculating the area and perimeter of a rectangular park. For instance, if the park’s length is 20 m and its breadth is 15 m:
• Area (space enclosed): length x breadth = 20 x 15 = 300 square meters.
• Perimeter (boundary length): 2 x (length + breadth) = 2 x (20 + 15) = 70 meters.
Mensuration involves practical applications like determining land size or fencing requirements, making it essential for real-world calculations.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What is the formula for perimeter and area chapter class 7?
The formulas for perimeter and area are essential in Class 7 mathematics: • Perimeter: Rectangle = 2 x (length + breadth), Square = 4 x side. • Area: Rectangle = length x breadth, Square = side x side, Triangle = 1/2 x base x height. These formulas are used to calculate the total boundary length (peRead more
The formulas for perimeter and area are essential in Class 7 mathematics:
• Perimeter: Rectangle = 2 x (length + breadth), Square = 4 x side.
• Area: Rectangle = length x breadth, Square = side x side, Triangle = 1/2 x base x height.
These formulas are used to calculate the total boundary length (perimeter) or the space enclosed by a 2D figure (area). They apply to various real-life scenarios like fencing and flooring.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
A piece of string is 36 cm long. What will be the length of each side, if it is used to form: a. A square, b. A triangle with all sides of equal length, and c. A hexagon (a six sided closed figure) with sides of equal length?
a. A square To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use ofRead more
a. A square
To form a square, its perimeter equals 4 x side length. The given string length of 36 cm acts as the perimeter. Using the formula: 36 = 4 x side, divide 36 by 4 to calculate the side length: side = 36 ÷ 4 = 9 cm. This ensures that each side of the square measures 9 cm, making full use of the string without any excess.
b. A triangle with all sides of equal length
In an equilateral triangle, all sides are equal. The perimeter of the triangle is calculated as 3 x side. Given a string length of 36 cm as the perimeter: 36 = 3 x side. Divide 36 by 3 to find side = 36 ÷ 3 = 12 cm. Thus, each side of the triangle will measure 12 cm, perfectly using the entire string length for the equilateral triangle.
c. A hexagon (six-sided figure) with sides of equal length
For a regular hexagon, all six sides are of equal length. Its perimeter is calculated as 6 x side. Using the given string length of 36 cm as the perimeter: 36 = 6 x side. Solving for side gives side = 36 ÷ 6 = 6 cm. This means each side of the hexagon measures 6 cm, ensuring the string is fully utilized to form the six-sided figure.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
What would be the cost of fencing a rectangular park whose length is 150 m and breadth is 120 m, if the fence costs `40 per metre?
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fRead more
The perimeter of the rectangular park is calculated as 2 x (length + breadth) = 2 x (150 + 120) = 2 x 270 = 540 m. Fencing costs 40 rupees per metre. Multiply the total perimeter by the cost per metre to find the total cost: 540 x 40 = 21600 rupees. This method ensures accurate cost estimation for fencing any rectangular area.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
A farmer has a rectangular field having length 230 m and breadth 160 m. He wants to fence it with 3 rounds of rope as shown. What is the total length of rope needed?
To calculate the total rope required, first find the perimeter of the rectangular field using 2 x (length + breadth). Substituting the values: 2 x (230 + 160) = 2 x 390 = 780 m. Since the farmer wants to fence the field with 3 rounds of rope, multiply the perimeter by 3: 3 x 780 = 2340 m. This ensurRead more
To calculate the total rope required, first find the perimeter of the rectangular field using 2 x (length + breadth). Substituting the values: 2 x (230 + 160) = 2 x 390 = 780 m. Since the farmer wants to fence the field with 3 rounds of rope, multiply the perimeter by 3: 3 x 780 = 2340 m. This ensures enough rope to surround the field three times, securing the boundary effectively.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/