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What is the gravitational field inside a uniform spherical shell?
Inside a uniform spherical shell, gravitational field is zero due to symmetry and the shell theorem. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncRead more
Inside a uniform spherical shell, gravitational field is zero due to symmetry and the shell theorem. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.
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What is the relationship between gravitational mass and inertial mass?
According to the equivalence principle, gravitational and inertial mass are equivalent, making their effects indistinguishable. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding. For more please visit here: httpsRead more
According to the equivalence principle, gravitational and inertial mass are equivalent, making their effects indistinguishable. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/
A metal ball of mass 2 kg moving with speed of 36 km/h has a head on collision with a stationary ball of mass 3 kg. If after collision, both the balls move as a single mass, then the loss in K.E. due to collision is
To calculate the loss in kinetic energy due to the collision, we first calculate the initial and final kinetic energies of the system. Step 1: Convert initial speed to m/s Initial speed of the moving ball = 36 km/h Speed in m/s = (36 × 1000) / (60 × 60) = 10 m/s Step 2: Calculate the initial kineticRead more
To calculate the loss in kinetic energy due to the collision, we first calculate the initial and final kinetic energies of the system.
Step 1: Convert initial speed to m/s
Initial speed of the moving ball = 36 km/h
Speed in m/s = (36 × 1000) / (60 × 60) = 10 m/s
Step 2: Calculate the initial kinetic energy (K.E.) of the system
Only the first ball is moving initially, so:
Initial K.E. = (1/2) m₁ v₁²
Where:
– m₁ = 2 kg (the moving ball mass)
– v₁ = 10 m/s (the velocity of the moving ball)
Initial K.E. = (1/2) × 2 × (10)²
Initial K.E. = 100 J
.
Step 3: Calculating the resulting velocity of the merged mass
Immediately after impact, the balls have merged as a single object mass
– Total mass = m₁ + m₂ = 2 kg + 3 kg = 5 kg
Applying the law of conservation of momentum:
Initial momentum = Final momentum
m₁ v₁ + m₂ v₂ = (m₁ + m₂) v
where:
– v₂ = 0 (a stationary ball)
Substitute:
(2 x 10) + (3 x 0) = 5v
20 = 5v
v = 4 m/s
Step 4: Find the final kinetic energy of the system (K.E.)
Final K.E. = (1/2) (m₁ + m₂) v²
Final K.E. = (1/2) × 5 × (4)²
Final K.E. = (1/2) × 5 × 16
Final K.E. = 40 J
Step 5: Calculate the loss in kinetic energy
Loss in K.E. = Initial K.E. − Final K.E.
Loss in K.E. = 100 J − 40 J
Loss in K.E. = 60 J
Final Answer:
Loss in kinetic energy due to collision is 60 J.
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How does the escape velocity on the Moon compare to that on Earth?
The escape velocity of the Moon is smaller due to its smaller mass and less radius than Earth. This is a question of Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/Read more
The escape velocity of the Moon is smaller due to its smaller mass and less radius than Earth. This is a question of Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/
250 N force is required to raise 75 kg mass from a pulley. If rope is pulled 12 m, then the load is lifted to 3 m, the efficiency of pulley system will be
We use the formula for efficiency of a pulley system: Efficiency = (Useful Work Output / Total Work Input) × 100 Step 1: Calculate Useful Work Output Useful work output is the work done in lifting the load. It is given by: Useful Work Output = Force × Distance lifted Where, - Force or weight of theRead more
We use the formula for efficiency of a pulley system:
Efficiency = (Useful Work Output / Total Work Input) × 100
Step 1: Calculate Useful Work Output
Useful work output is the work done in lifting the load. It is given by:
Useful Work Output = Force × Distance lifted
Where,
– Force or weight of the load = mass × gravitational acceleration
– Weight of the load = 75 kg × 9.8 m/s² = 735 N
– Distance lifted = 3 m
Therefore, the useful work output is:
Work Output = 735 N × 3 m = 2205 J
Step 2: Calculate Total Work Input
The total work input is the work done in pulling the rope. This is calculated as:
Total Work Input = Force applied × Distance pulled
Where:
– Force applied = 250 N
– Distance pulled = 12 m
Therefore, the total work input is:
Work Input = 250 N × 12 m = 3000 J
Step 3: Calculate Efficiency
Now, we can find the efficiency:
Efficiency = (Work Output / Work Input) × 100
Efficiency = (2205 J / 3000 J) × 100 ≈ 73.5%
The closest option is 75%.
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