Share & grow the world's knowledge!
We want to connect the people who have knowledge to the people who need it, to bring together people with different perspectives so they can understand each other better, and to empower everyone to share their knowledge.
Why can light not escape a black hole?
Black Hole Escape Velocity Even light cannot get out of black hole because black hole's escape velocity is larger than the velocity of light. This question belongs to Chapter 7 physics Class 11th NCERT. Question: From Chapter 7. Gravitation. Answer on the basis of your understanding. For more pleaseRead more
Black Hole Escape Velocity Even light cannot get out of black hole because black hole’s escape velocity is larger than the velocity of light. This question belongs to Chapter 7 physics Class 11th NCERT. Question: From Chapter 7. Gravitation. Answer on the basis of your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/
A child is sitting on a swing. Its minimum and maximum heights from the ground 0.75 m and 2 m respectively, its maximum speed will be
To find the maximum speed of the child on the swing, we use the principle of conservation of energy. The total mechanical energy is conserved, so the loss in potential energy is converted to kinetic energy at the lowest point. Step 1: Calculate the change in potential energy The difference in heightRead more
To find the maximum speed of the child on the swing, we use the principle of conservation of energy. The total mechanical energy is conserved, so the loss in potential energy is converted to kinetic energy at the lowest point.
Step 1: Calculate the change in potential energy
The difference in height between the maximum and minimum positions is:
h = Maximum height − Minimum height
h = 2 m − 0.75 m
h = 1.25 m
Step 2: Apply conservation of energy law
At the highest point all the energy will be potential. At the lowest point, it will be the kinetic energy where the potential is converted into this kinetic energy.
K.E = P.E.
(1/2)mv² = mgh
Given:
– m = mass of child (gets eliminated on both the sides)
g = acceleration due to gravity = 10 m/s²
h = height = 1.25 m
– v = maximum speed
Rearrange the equation to find v:
v² = 2gh
v = √(2gh)
Substitute the values:
nv = √(2 × 10 × 1.25)
nv = √(25)
nv = 5 m/s
The maximum speed of the child on the swing is 5 m/s.
Click here for more information:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-5/
What happens to the orbital period of a satellite if its orbital radius increases? Description: Consider Kepler’s third law.
By Kepler’s third law, T² ∝ r³. As the orbital radius increases, the period also increases. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutRead more
By Kepler’s third law, T² ∝ r³. As the orbital radius increases, the period also increases. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/
A bullet of mass 10 g leaves a rifle at an initial velocity of 100 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joule overcoming the resistance of air will be
To calculate the work done overcoming the resistance of air, we will need to determine the change in kinetic energy. Step 1: Write down the formula for work done The work done by air resistance is equal to the loss in the kinetic energy of the bullet. The formula for kinetic energy is: K.E. = (1/2)Read more
To calculate the work done overcoming the resistance of air, we will need to determine the change in kinetic energy.
Step 1: Write down the formula for work done
The work done by air resistance is equal to the loss in the kinetic energy of the bullet. The formula for kinetic energy is:
K.E. = (1/2) m v²
Where:
– m = mass of the bullet = 10 g = 0.01 kg
– v = velocity of the bullet (initial and final)
Step 2: Calculate the initial and final kinetic energies
Initial velocity, u = 100 m/s
Final velocity, v = 500 m/s
Initial kinetic energy:
K.E.₁ = (1/2) m u²
K.E.₁ = (1/2) × 0.01 × (100)²
K.E.₁ = 0.005 × 10000
K.E.₁ = 50 J
Final kinetic energy:
K.E.₂ = (1/2) m v²
K.E.₂ = (1/2) × 0.01 × (500)²
K.E.₂ = 0.005 × 250000
K.E.₂ = 1250 J
Step 3: Find the work done
The work done in overcoming air resistance is the difference in kinetic energy:
Work done = K.E.₂ − K.E.₁
Work done = 1250 − 50
Work done = 1200 J
The work done in overcoming the resistance of air is 1200 J.
Click here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-5/
How does escape velocity depend on the mass of the planet?
The escape velocity (v_e) is the minimum velocity an object must have in order to break free from a planet's gravitational influence without further propulsion. It is derived from the balance between the object's kinetic energy and the planet's gravitational potential energy. The formula for escapeRead more
The escape velocity (v_e) is the minimum velocity an object must have in order to break free from a planet’s gravitational influence without further propulsion. It is derived from the balance between the object’s kinetic energy and the planet’s gravitational potential energy.
The formula for escape velocity is:
v_e = √(2GM / R)
Where:
– v_e is the escape velocity,
– G is the gravitational constant (6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²),
– M is the mass of the planet,
– R is the radius of the planet.
From this formula, we can see that escape velocity depends on the mass of the planet (M) in a square root relationship. Specifically, the escape velocity increases with the square root of the mass. This means that for a planet with greater mass, the escape velocity will be higher.
Example:
– A planet with a higher mass will have a higher escape velocity.
– A smaller planet or a planet with lower mass will have a lower escape velocity.
In summary:
– Escape velocity is directly proportional to the square root of the mass of the planet.
This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/