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If momentum decreases by 20 %, K.E. will decrease by
To find the percentage decrease in kinetic energy (K.E.) when momentum decreases by 20%, we have the following relations: 1. Momentum (p) is defined as: p = m * v where m is the mass and v is the velocity. 2. Kinetic energy (K.E.) is defined as: K.E. = (1/2) * m * v². 3. If momentum decreases by 20%Read more
To find the percentage decrease in kinetic energy (K.E.) when momentum decreases by 20%, we have the following relations:
1. Momentum (p) is defined as:
p = m * v
where m is the mass and v is the velocity.
2. Kinetic energy (K.E.) is defined as:
K.E. = (1/2) * m * v².
3. If momentum decreases by 20%, then the new momentum is given by p’.
p’ = p – 0.2p = 0.8p.
4. As momentum is directly proportional to mass and velocity, we can express the new velocity, v’, in terms of the original velocity, v, as:
p’ = m * v’ = 0.8(m * v).
5. Divide both sides by m
v’ = 0.8v.
6. We can now compute the new kinetic energy, K.E.’:
K.E.’ = (1/2) * m * (v’)²
= (1/2) * m * (0.8v)²
= (1/2) * m * 0.64v²
= 0.64 * (1/2) * m * v²
= 0.64 * K.E.
7. The percentage decrease in kinetic energy is:
Percentage decrease = [(K.E. – K.E.’) / K.E.] * 100
= [(K.E. – 0.64K.E.) / K.E.] * 100
= (0.36K.E. / K.E.) * 100 = 36%.
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Electrons are emitted from a photosensitive surface when it is illuminated by green light but electron emission does not take place by yellow light. Will the electrons be emitted when the surface is illuminated by (1) red light, and (ii) blue light?
(1) Electrons will not be emitted with red light because its frequency is lower than green and yellow light, providing insufficient energy. (2) Electrons will be emitted with blue light as its frequency is higher than green light, exceeding the threshold frequency. For more visit here: https://www.tRead more
(1) Electrons will not be emitted with red light because its frequency is lower than green and yellow light, providing insufficient energy.
(2) Electrons will be emitted with blue light as its frequency is higher than green light, exceeding the threshold frequency.
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Where does gravitational force act on a body?
Gravitational force acts on the center of mass, which is the average position of mass in the body. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncerRead more
Gravitational force acts on the center of mass, which is the average position of mass in the body. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.
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Why do objects appear weightless in artificial satellites?
The satellites and their contents are in free fall. They appear weightless. This is a question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/phRead more
The satellites and their contents are in free fall. They appear weightless. This is a question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Answer according to your understanding.
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How does gravitational force compare to electromagnetic force?
Electromagnetic forces are significantly stronger than gravitational forces at the atomic and molecular levels. Electromagnetic forces are significantly stronger than gravitational forces at the atomic and molecular levels. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/clRead more
Electromagnetic forces are significantly stronger than gravitational forces at the atomic and molecular levels. Electromagnetic forces are significantly stronger than gravitational forces at the atomic and molecular levels.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/