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An electric motor exerts a force of 40 N on a cable and pulls it by distance of 30 m in one minute. The power supplied by the motor (in watt) is
Use the formula for power to calculate how much power the motor supplies. Power (P) = Work done (W) / Time (t) Step 1: Calculate work done Work done (W) is given by the formula W = Force × Distance Given: Force (F) = 40 N Distance (d) = 30 m Now, calculate the work done: W = 40 N × 30 m W = 1200 J (Read more
Use the formula for power to calculate how much power the motor supplies.
Power (P) = Work done (W) / Time (t)
Step 1: Calculate work done
Work done (W) is given by the formula
W = Force × Distance
Given:
Force (F) = 40 N
Distance (d) = 30 m
Now, calculate the work done:
W = 40 N × 30 m
W = 1200 J (joules)
Step 2: Convert time from minutes to seconds
Since the motor pulls the cable in one minute,
Time (t) = 1 minute = 60 seconds
Step 3: Calculate the power
Now, substitute the values into the power formula:
P = W / t
P = 1200 J / 60 s
P = 20 W
Final Answer:
The power supplied by the motor is 20 watts.
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Two metals A and B have work functions 2eV and 5eV, respectively. Which metal has a lower threshold wavelength?
Metal B has a lower threshold wavelength because threshold wavelength (λ th ) is inversely proportional to the work function (W) as λ th = hc/W . A higher work function results in a shorter threshold wavelength. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapRead more
Metal B has a lower threshold wavelength because threshold wavelength (λ th ) is inversely proportional to the work function (W) as λ th = hc/W . A higher work function results in a shorter threshold wavelength.
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A 10 kg ball moving with velocity 2 m/s collides with a 20 kg mass initially at rest. If both of them coalesce, the final velocity of combined mass is
To determine the final velocity of the combined mass after the collision, we can use the principle of conservation of momentum. Given: - Mass of ball 1 (m₁) = 10 kg - Velocity of ball 1 (u₁) = 2 m/s - Mass of ball 2 (m₂) = 20 kg - Velocity of ball 2 (u₂) = 0 m/s (initially at rest) Step 1: CalculateRead more
To determine the final velocity of the combined mass after the collision, we can use the principle of conservation of momentum.
Given:
– Mass of ball 1 (m₁) = 10 kg
– Velocity of ball 1 (u₁) = 2 m/s
– Mass of ball 2 (m₂) = 20 kg
– Velocity of ball 2 (u₂) = 0 m/s (initially at rest)
Step 1: Calculate initial momentum
Initial momentum (p_initial) = m₁ * u₁ + m₂ * u₂
p_initial = (10 kg * 2 m/s) + (20 kg * 0 m/s)
p_initial = 20 kg·m/s
Step 2: Compute the final velocity after collision
Let v be the final velocity of the combined mass (m₁ + m₂).
After the collision, the total mass is:
m_total = m₁ + m₂ = 10 kg + 20 kg = 30 kg
According to the conservation of momentum:
p_initial = p_final
20 kg·m/s = (m₁ + m₂) * v
20 kg·m/s = 30 kg * v
Step 3: Solve for v
v = 20 kg·m/s / 30 kg
v = 2/3 m/s
Final Answer:
The final velocity of the combined mass is 2/3 m/s.
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A body of mass 5 kg, moving with velocity 10 m/sec collides with another body of the mass 20 kg at rest and comes to rest. The velocity of the second body due to collision is
We can apply the principle of conservation of momentum to calculate the velocity of the second body after the collision. Step 1: Write the momentum before and after collision Let, m₁ = Mass of the first body = 5 kg u₁ = Initial velocity of the first body = 10 m/s m₂ = Mass of the second body = 20 kgRead more
We can apply the principle of conservation of momentum to calculate the velocity of the second body after the collision.
Step 1: Write the momentum before and after collision
Let,
m₁ = Mass of the first body = 5 kg
u₁ = Initial velocity of the first body = 10 m/s
m₂ = Mass of the second body = 20 kg
– Starting velocity of the second body (u₂) = 0 m/s (at rest)
– Final velocity of both bodies after collision (v₁) = 0 m/s (first body comes to rest)
– Final velocity of the second body (v₂) = ?
Applying the principle of conservation of momentum:
Initial momentum = Final momentum
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂
(5 kg × 10 m/s) + (20 kg × 0 m/s) = (5 kg × 0 m/s) + (20 kg × v₂)
Step 2: Find v₂
50 kg·m/s = 0 + 20 kg × v₂
50 kg·m/s = 20 kg × v₂
Divide both sides by 20 kg
v₂ = 50 kg·m/s / 20 kg
v₂ = 2.5 m/s
Final Answer:
The velocity of the second body due to the collision is 2.5 m/sec.
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Name the phenomenon which shows the quantum nature of electromagnetic radiation.
The phenomenon that demonstrates the quantum nature of electromagnetic radiation is the photoelectric effect, where light ejects electrons from a material, showing light's particle-like behavior as discrete photons. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/Read more
The phenomenon that demonstrates the quantum nature of electromagnetic radiation is the photoelectric effect, where light ejects electrons from a material, showing light’s particle-like behavior as discrete photons.
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