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The center of mass of a two-particle system lies closer to:
The center of mass of a two-particle system lies closer to the particle with the greater mass. This is because the position of the center of mass (COM) is calculated as a weighted average of the positions of the two particles, with their respective masses serving as the weights. Mathematically, theRead more
The center of mass of a two-particle system lies closer to the particle with the greater mass. This is because the position of the center of mass (COM) is calculated as a weighted average of the positions of the two particles, with their respective masses serving as the weights.
Mathematically, the center of mass for a two-particle system can be expressed as:
\[ x_{COM} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \]
Here:
– \( m_1 \) and \( m_2 \) are the masses of the two particles.
– \( x_1 \) and \( x_2 \) are the positions of the two particles along a straight line.
From this formula, it is clear that:
– If \( m_1 > m_2 \), the center of mass will be closer to \( x_1 \).
– If \( m_2 > m_1 \), the center of mass will be closer to \( x_2 \).
This principle holds true regardless of the spatial dimension, with similar calculations extending to three-dimensional systems using the vector positions of the particles.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational Motion. Give answer according to your understanding.
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Which of the following is a condition for static equilibrium of a rigid body?
For static equilibrium, there should be no linear or rotational motion. Thus, both net force and net torque must be zero. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of Particle and Rotational Motion. Give answer according to your understanding. For more pRead more
For static equilibrium, there should be no linear or rotational motion. Thus, both net force and net torque must be zero. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of Particle and Rotational Motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
The kinetic energy of a rolling body depends on:
In rolling motion, the total kinetic energy is the sum of translational 1/2ЁЭСАЁЭСг┬▓ and rotational 1/2ЁЭР╝ЁЭЬФ┬▓ kinetic energy. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particles and Rotational Motion. Give answer according to your understanding. For more pleasRead more
In rolling motion, the total kinetic energy is the sum of translational 1/2ЁЭСАЁЭСг┬▓ and rotational 1/2ЁЭР╝ЁЭЬФ┬▓ kinetic energy. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particles and Rotational Motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
If a body is rotating with uniform angular velocity, which of the following quantities is zero?
For uniform angular velocity, there is no change in ЁЭЬФ over time, so angular acceleration ЁЭЫ╝ and torque ЁЭЬП are both zero. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational Motion Give answer according to your understanding. For more pleasRead more
For uniform angular velocity, there is no change in ЁЭЬФ over time, so angular acceleration ЁЭЫ╝ and torque ЁЭЬП are both zero. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational Motion Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
What is the center of mass of a uniform semicircular ring of radius ЁЭСЕ ?
The center of mass of a uniform semicircular ring lies at a distance 2ЁЭСЕ/ЁЭЬЛ along the axis of symmetry, derived using integration over the arc. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational motion. Give answer according to your underRead more
The center of mass of a uniform semicircular ring lies at a distance 2ЁЭСЕ/ЁЭЬЛ along the axis of symmetry, derived using integration over the arc.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6. System of particle and Rotational motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/