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A particle of mass 𝑚 is moving in a circular path of radius 𝑟 with constant speed 𝑣 . What is its angular momentum about the center of the circle?
In circular motion, angular momentum is 𝐿 = 𝑟⋅𝑚𝑣⋅sin 𝜃 = 90° , L=mvr. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncerRead more
In circular motion, angular momentum is 𝐿 = 𝑟⋅𝑚𝑣⋅sin 𝜃 = 90° , L=mvr.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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When light travels from a rarer to a denser medium, the speed of light decreases. Does the reduction in speed imply a reduction in the energy?
No, the reduction in speed of light when it enters a denser medium does not imply a reduction in energy. The energy of light depends on its frequency, which remains constant during refraction. Only the wavelength and speed change, conserving the light's energy. For more visit here: https://www.tiwarRead more
No, the reduction in speed of light when it enters a denser medium does not imply a reduction in energy. The energy of light depends on its frequency, which remains constant during refraction. Only the wavelength and speed change, conserving the light’s energy.
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A solid sphere rolls without slipping down an inclined plane. What fraction of its total energy is rotational kinetic energy?
When a solid sphere rolls without slipping down an inclined plane, its total energy is distributed between translational kinetic energy and rotational kinetic energy. The fraction of its total energy that is rotational kinetic energy can be derived as follows: 1. Total Energy (E): E = KEₜᵣₐₙₛₗₐₜᵢₒₙₐRead more
When a solid sphere rolls without slipping down an inclined plane, its total energy is distributed between translational kinetic energy and rotational kinetic energy. The fraction of its total energy that is rotational kinetic energy can be derived as follows:
1. Total Energy (E):
E = KEₜᵣₐₙₛₗₐₜᵢₒₙₐₗ + KEᵣₒₜₐₜᵢₒₙₐₗ
2. Translational Kinetic Energy:
KEₜᵣₐₙₛₗₐₜᵢₒₙₐₗ = 1/2Mv², where M is the mass and v is the velocity of the center of mass.
3. Rotational Kinetic Energy:
KEᵣₒₜₐₜᵢₒₙₐₗ = 1/2Iω², where I is the moment of inertia and ω is the angular velocity. For a solid sphere, I = 2/5MR² and ω = v/R. Substituting ω, KEᵣₒₜₐₜᵢₒₙₐₗ = 1/2.2/5MR². v²/R² = 1/5Mv².
4. Total Energy Expression:
E = 1/2Mv² + 1/5Mv² = 7/10Mv².
5. Fraction of Rotating Energy:
Fraction of Rotation Energy = KEᵣₒₜₐₜᵢₒₙₐₗ/E = (1/5Mv²) / (7/10 Mv²) = 2/7.
The fraction of the total energy that is rotational kinetic energy is 2/7.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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What is the physical significance of the radius of gyration?
The radius of gyration 𝑘 gives an equivalent distance from the axis at which the entire mass of the body can be assumed to be concentrated to produce the same moment of inertia. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion.Read more
The radius of gyration 𝑘 gives an equivalent distance from the axis at which the entire mass of the body can be assumed to be concentrated to produce the same moment of inertia.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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If the net external force acting on a system of particles is zero, what can be said about the motion of its center of mass?
If the net external force is zero, the acceleration of the center of mass is also zero. Hence, it moves with constant velocity according to Newton’s first law of motion. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give anRead more
If the net external force is zero, the acceleration of the center of mass is also zero. Hence, it moves with constant velocity according to Newton’s first law of motion. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/