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  1. In uniform circular motion, the acceleration (centripetal acceleration) always points towards the center of the circle, perpendicular to the velocity vector. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer accordiRead more

    In uniform circular motion, the acceleration (centripetal acceleration) always points towards the center of the circle, perpendicular to the velocity vector. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.

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    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/

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  2. The radius of gyration 𝑘 is defined such that 𝐼 = 𝑀𝑘², where 𝑀 is the total mass of the object. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more please visit here: https://Read more

    The radius of gyration 𝑘 is defined such that 𝐼 = 𝑀𝑘², where 𝑀 is the total mass of the object. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/

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  3. When net torque is zero, there is no change in angular momentum. According to the principle of conservation of angular momentum, 𝐿 = constant. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your undeRead more

    When net torque is zero, there is no change in angular momentum. According to the principle of conservation of angular momentum, 𝐿 = constant. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/

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  4. (i) No Chromatic Aberration: Reflecting telescopes avoid color distortions (chromatic aberration) since mirrors do not refract light. (ii) Larger Apertures: Mirrors can be made much larger than lenses, allowing for more light gathering. (iii) No Lens Sagging: Mirrors support their own weight, unlikeRead more

    (i) No Chromatic Aberration: Reflecting telescopes avoid color distortions (chromatic aberration) since mirrors do not refract light.
    (ii) Larger Apertures: Mirrors can be made much larger than lenses, allowing for more light gathering.
    (iii) No Lens Sagging: Mirrors support their own weight, unlike lenses, which can sag and distort the image due to gravity.

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    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-9/

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  5. To determine the potential energy loss of a 20 kg ball dropped from 50 cm height, we shall use the potential energy formula: Potential Energy = mass × gravitational acceleration × height Mass (m) = 20 kg Height (h) = 50 cm = 0.5 m Gravitational acceleration (g) ≈ 9.8 m/s² Putting all these values inRead more

    To determine the potential energy loss of a 20 kg ball dropped from 50 cm height, we shall use the potential energy formula:

    Potential Energy = mass × gravitational acceleration × height

    Mass (m) = 20 kg
    Height (h) = 50 cm = 0.5 m
    Gravitational acceleration (g) ≈ 9.8 m/s²

    Putting all these values into the formula,

    Potential Energy = 20 kg × 9.8 m/s² × 0.5 m
    Potential Energy = 20 kg × 4.9 m²/s²
    Potential Energy = 98 J

    This implies that the potential energy of the ball has decreased by 98 J.

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    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-5/

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