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  1. Performing Prānāyāma under a teacher ensures correct technique, which is essential for effective results and avoiding harm. A teacher can guide breathing practices, correct mistakes, and address individual challenges. Proper guidance helps practitioners maintain safety, achieve intended benefits, anRead more

    Performing Prānāyāma under a teacher ensures correct technique, which is essential for effective results and avoiding harm. A teacher can guide breathing practices, correct mistakes, and address individual challenges. Proper guidance helps practitioners maintain safety, achieve intended benefits, and progress steadily. Teachers also provide personalized instructions and ensure alignment with traditional practices, creating a supportive environment for holistic growth and mastery of Prānāyāma techniques.

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  2. Stress is defined as the internal restoring force per unit area developed in a material when it is deformed due to an external force. It is expressed as 𝜎 = 𝐹/𝐴. This question related to Chapter 8 physics Class 11th NCERT. From the Chapter 8. Mechanical Properties of Solids. Give answer according toRead more

    Stress is defined as the internal restoring force per unit area developed in a material when it is deformed due to an external force. It is expressed as 𝜎 = 𝐹/𝐴. This question related to Chapter 8 physics Class 11th NCERT. From the Chapter 8. Mechanical Properties of Solids. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/

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  3. The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula: A = (π × d²) / 4 Step 1: Determine the areas First wire (diameter = 1 mm): A₁ = (π × 1²) / 4 = π / 4 Second wire (diameter = 2 mm): A₂ = (π × 2²) / 4 = 4π / 4 = π The area of the seconRead more

    The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula:

    A = (π × d²) / 4

    Step 1: Determine the areas
    First wire (diameter = 1 mm):
    A₁ = (π × 1²) / 4 = π / 4

    Second wire (diameter = 2 mm):
    A₂ = (π × 2²) / 4 = 4π / 4 = π
    The area of the second wire is **4 times** the area of the first wire.

    Step 2: Calculate the breaking tension
    Breaking tension is proportional to the area.

    For the first wire:
    T₁ = 1000 N

    For the second wire:
    T₂ = 4 × T₁ = 4 × 1000 = 4000 N

    Click here for more:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/

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  4. For sectional breathing, postures like Vajrāsana, Vīrāsana, Padmāsana, and Sukhāsana are recommended. These sitting positions ensure the spine remains erect, the body stays relaxed, and the breathing process is unhindered. Maintaining a straight spine aligns energy flow, while relaxed facial and bodRead more

    For sectional breathing, postures like Vajrāsana, Vīrāsana, Padmāsana, and Sukhāsana are recommended. These sitting positions ensure the spine remains erect, the body stays relaxed, and the breathing process is unhindered. Maintaining a straight spine aligns energy flow, while relaxed facial and body muscles support mindfulness. Practicing in these postures enhances Prānāyāma’s effectiveness, enabling deeper, rhythmic breathing and fostering physical and mental balance.

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  5. The ratio of longitudinal stress to longitudinal strain is called Young's Modulus or the Modulus of Elasticity. It is a measure of the stiffness of a material and is expressed mathematically as: \[ E = \frac{\text{Longitudinal Stress}}{\text{Longitudinal Strain}} \] Where: - \(E\) is Young's ModulusRead more

    The ratio of longitudinal stress to longitudinal strain is called Young’s Modulus or the Modulus of Elasticity. It is a measure of the stiffness of a material and is expressed mathematically as:

    \[
    E = \frac{\text{Longitudinal Stress}}{\text{Longitudinal Strain}}
    \]

    Where:
    – \(E\) is Young’s Modulus (typically measured in pascals, Pa).
    – Longitudinal stress is the force applied per unit area (\(\sigma = \frac{F}{A}\)).
    – Longitudinal strain is the deformation per unit length (\(\varepsilon = \frac{\Delta L}{L}\)).

    Young’s Modulus is a fundamental property of materials, determining how they deform under tensile or compressive loads.
    This question related to Chapter 8 physics Class 11th NCERT. From the Chapter 8. Mechanical Properties of Solids. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/

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