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If in a wire of Young’s modulus Y, longitudinal strain X is produced, then the value of potential energy stored in its unit volume will be
Formula: The potential energy per unit volume of a taut wire may be given as follows: Energy per unit volume = ½ × Stress × Strain For a wire: Tension = Stress Stress = Y × Strain Substituting Stress to above equation: Potential Energy per unit volume = 1/2 x (Yx X) × X= 0.5Yx² Click for more: hRead more
Formula:
The potential energy per unit volume of a taut wire may be given as follows:
Energy per unit volume = ½ × Stress × Strain
For a wire:
Tension = Stress
Stress = Y × Strain
Substituting Stress to above equation:
Potential Energy per unit volume = 1/2 x (Yx X) × X= 0.5Yx²
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What is the main feature of Rutherford’s atom model?
Rutherford's atomic model proposed that an atom consists of a dense, positively charged nucleus containing most of its mass, surrounded by electrons orbiting in empty space. It introduced the concept of a nuclear atom but couldn't explain atomic stability or spectral lines. For more visit here: httpRead more
Rutherford’s atomic model proposed that an atom consists of a dense, positively charged nucleus containing most of its mass, surrounded by electrons orbiting in empty space. It introduced the concept of a nuclear atom but couldn’t explain atomic stability or spectral lines.
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A thick copper rope of density 1.5 x 10³ kgm⁻³ and Young’s modulus 5 x 10⁶ Nm⁻², 8 m in length, its length due to its own weight is
The extension due to the weight of the rope can be found using the following formula: ΔL = (F L) / (A Y) Where: - F = Force due to weight = mg - L = Length of the rope = 8 m - A = Cross-sectional area of the rope - Y = Young's modulus - m = mass of the rope = density × volume - Volume = A × L AfterRead more
The extension due to the weight of the rope can be found using the following formula:
ΔL = (F L) / (A Y)
Where:
– F = Force due to weight = mg
– L = Length of the rope = 8 m
– A = Cross-sectional area of the rope
– Y = Young’s modulus
– m = mass of the rope = density × volume
– Volume = A × L
After computation, we get that the stretch is approximately:
ΔL = 9.6 x 10⁻⁵ m
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A metallic rod of length l and cross – sectional area A is made of a material of Young’s modulus Y. If the rod is elongated by an amount y, then the work done is proportional to
The work done (W) in elongating a rod is given by the formula: W = 1/2 × Stress × Strain × Volume Where: - Stress = Force / Area - Strain = ΔL / L (elongation per unit length) As elongation, ΔL, is proportional to the applied force and Young's modulus, work done is proportional to the square of theRead more
The work done (W) in elongating a rod is given by the formula:
W = 1/2 × Stress × Strain × Volume
Where:
– Stress = Force / Area
– Strain = ΔL / L (elongation per unit length)
As elongation, ΔL, is proportional to the applied force and Young’s modulus, work done is proportional to the square of the elongation.
Therefore, work done is proportional to y².
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A long piece of rubber is wider than it is thick. When it is stretched in length by some amount
When a rubber is stretched in length, it experiences a deformation in which the material attempts to preserve its volume. Since the length increases, the cross-sectional area reduces, bringing down the thickness. In most cases, width can increase as rubber stretches in length to preserve the overallRead more
When a rubber is stretched in length, it experiences a deformation in which the material attempts to preserve its volume. Since the length increases, the cross-sectional area reduces, bringing down the thickness. In most cases, width can increase as rubber stretches in length to preserve the overall volume.
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