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  1. (i) Both circles are within the screen because their centers plus or minus their radii stay between 0 and 800 for width and 0 and 600 for height. (ii) The distance between center A (100, 150) and center B (250, 230) is calculated as 170 pixels. The sum of their radii is 80 plus 100, which equals 180Read more

    (i) Both circles are within the screen because their centers plus or minus their radii stay between 0 and 800 for width and 0 and 600 for height. (ii) The distance between center A (100, 150) and center B (250, 230) is calculated as 170 pixels. The sum of their radii is 80 plus 100, which equals 180 pixels. Since the distance between the centers is less than the combined radii, the two circular icons must overlap or intersect.

     

    For Detailed Solutions:

    Visit NCERT Solutions for Class 9 Ganita Manjari Chapter 1 Orienting Yourself: The Use of Coordinates Question Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-1/

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  2. By calculating the distances between the points, we find that all four sides are equal to the square root of 10 units. To confirm it is a square, we check the diagonals: both AC and BD are equal to the square root of 20 units. Since all sides are equal and both diagonals are equal, ABCD is a perfectRead more

    By calculating the distances between the points, we find that all four sides are equal to the square root of 10 units. To confirm it is a square, we check the diagonals: both AC and BD are equal to the square root of 20 units. Since all sides are equal and both diagonals are equal, ABCD is a perfect square. The area is calculated by squaring the side length, which gives a total of 10 square units.

     

    For Detailed Solutions:

    Visit NCERT Solutions for Class 9 Ganita Manjari Chapter 1 Orienting Yourself: The Use of Coordinates Question Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-1/

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  3. NCERT Solutions for Class 9 Sanskrit Sharada (2026–27) provide detailed, chapter-wise answers according to the latest NCERT syllabus and NEP 2020 guidelines. These solutions cover all sixteen chapters with clear explanations of grammar, word meanings and exercises. With simple language and accurateRead more

    NCERT Solutions for Class 9 Sanskrit Sharada (2026–27) provide detailed, chapter-wise answers according to the latest NCERT syllabus and NEP 2020 guidelines. These solutions cover all sixteen chapters with clear explanations of grammar, word meanings and exercises. With simple language and accurate solutions, students can achieve better academic performance in new Class 9 Sanskrit Sharada book (संस्कृत शारदा).

    Class 9 NCERT/CBSE New book Sanskrit Sharada Chapter List:

    Chapter 1 – सत्यं शिवं सुन्दरं संस्कृतम्

    Chapter 2 – सुखस्य मूलं धर्म: धर्मस्य मूलम् अर्थ:

    Chapter 3 – आत्मवत्सर्वभूतेषु यः पश्यति सः पण्डितः

    Chapter 4 – न खलु वयस्तेजसो हेतुः

    Chapter 5 – एषा सा कृतकबुद्धि: मानवबुद्ध: सहकरी

    Chapter 6 – मनःपूतं समाचरेत

    Chapter 7 – उपायं चिन्तयेत प्राज्ञस्तथापायं च चिन्तयेत

    Chapter 8 – अन्नाद् आनन्दं प्रति

    Chapter 9 – कृतं प्रतिकृतं भूयादेष धर्मः सनातनः

    Chapter 10 – णमो अरिहन्ताणम्

    Chapter 11 – वर्णोच्चारण-शिक्षा २

    Chapter 12 – अन्वयः

    Chapter 13 – समासः

    Chapter 14 – वाच्यम्

    Chapter 15 – शब्दरूपाणि

    Chapter 16 – धातुरूपाणि

     

    For more NCERT Solutions of Class 9 Sanskrit Sharada (संस्कृत शारदा) All Chapter Solutions (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/sanskrit/

     

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  4. Based on the grid layout, point D1 is located on the horizontal axis. We determine its position by counting 9 units from the origin along the North-South/East-West grid lines as described in the text. Since D1 lies exactly on the x-axis, its vertical position or y-coordinate is 0. Therefore, the exaRead more

    Based on the grid layout, point D1 is located on the horizontal axis. We determine its position by counting 9 units from the origin along the North-South/East-West grid lines as described in the text. Since D1 lies exactly on the x-axis, its vertical position or y-coordinate is 0. Therefore, the exact coordinates of D1 are written as (9, 0), representing its horizontal and vertical distances respectively.

     

    For Detailed Solutions:

    Visit NCERT Solutions for Class 9 Ganita Manjari Chapter 1 Orienting Yourself: The Use of Coordinates Question Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-1/

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  5. To compare the doors, we calculate their lengths. The room door width is 2.5 units (11.5 minus 9). The bathroom door lies on the y-axis, so we subtract its y-coordinates: 4 minus 1.5 equals 2.5 units. Since both calculations result in a distance of 2.5 units, the bathroom door is neither narrower noRead more

    To compare the doors, we calculate their lengths. The room door width is 2.5 units (11.5 minus 9). The bathroom door lies on the y-axis, so we subtract its y-coordinates: 4 minus 1.5 equals 2.5 units. Since both calculations result in a distance of 2.5 units, the bathroom door is neither narrower nor wider; both the room door and the bathroom door are equal in width.

     

    For Detailed Solutions:

    Visit NCERT Solutions for Class 9 Ganita Manjari Chapter 1 Orienting Yourself: The Use of Coordinates Question Answer:

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-1/

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