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A body moves a distance of 10 m under the action of force F = 10N. If the work done is 25J, the angle which the force makes with the direction of motion is
In any movement of a body under the effect of a force, work is done and the amount depends upon the force, distance covered and angle between force and direction. Here it is given that a body moves 10 m under the influence of a 10 N force and the amount of work is 25 Joules. We establish the angle mRead more
In any movement of a body under the effect of a force, work is done and the amount depends upon the force, distance covered and angle between force and direction. Here it is given that a body moves 10 m under the influence of a 10 N force and the amount of work is 25 Joules.
We establish the angle made between the force and the direction of motion for us to deduce the relation between these parameters. Work done is essentially a product of force, displacement, and the cosine of the angle between them. In this context, work done here is lesser than the maximum possible work which would have occurred if the force had acted in full in the direction of motion. This means that the force is not completely aligned with the motion. A part of the force works in doing work while the other part of it is perpendicular to the motion.
From the values above, we find that the angle between the force and motion is 60 degrees. Thus, this force is partially effective in causing displacement; its directional component is the cause of the work done. This example goes to prove that the angle determines work.
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A uniform chain of length 2 m is kept on a table such that a length of 60 cm hangs freely from the edge of the table. The total mass of the chain is 4 kg. What is the work done in pulling the entire chain on the table?
To find the work performed in pulling a chain of uniform density onto a table, let us consider a chain 2 meters long, the total mass being 4 kilograms. When put on the table, it overhangs the edge by 60 centimeters. The work performed to raise this overhanging part against the force of gravity can bRead more
To find the work performed in pulling a chain of uniform density onto a table, let us consider a chain 2 meters long, the total mass being 4 kilograms. When put on the table, it overhangs the edge by 60 centimeters. The work performed to raise this overhanging part against the force of gravity can be evaluated using the formula for gravitational potential energy.
Initially, the hanging portion of the chain has a mass that corresponds to its length. Since the entire chain weighs 4 kilograms, the mass of the hanging segment, which is 60 centimeters, is proportionately lighter. As the chain is pulled onto the table, the work required to lift this hanging part involves raising it to a height that gradually reduces to zero.
Since this is the average height of the hanging segment, it is the height to which each mass was lifted to get the work done. The work done against gravity is calculated by multiplying the mass, gravitational force, and height. Using these considerations, the total work done in pulling the whole chain onto the table is found to be about 3.6 joules, which is the energy expended in overcoming the force of gravity in repositioning the chain.
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A body is moved along a straight line by a machine delivering constant power. The distance moved by the body in time t is proportional to
When a machine applies constant power to move a body along a straight line, one may understand the relation of the distance covered by the body with time through the concept of power. Power is the rate of doing work or transferring energy. When the machine gives constant power, it means that the eneRead more
When a machine applies constant power to move a body along a straight line, one may understand the relation of the distance covered by the body with time through the concept of power. Power is the rate of doing work or transferring energy. When the machine gives constant power, it means that the energy being given to the body remains constant with respect to time.
When the body moves, its velocity increases due to the continuous supply of energy. When the velocity of the body increases, the force acting upon it decreases because the product of force and velocity must remain constant in order to keep the power constant. This variation in force and velocity affects the distance traveled by the body over time.
Analysis of the dynamics of the motion, taking place under constant power, reveals that the distance moved by the body is proportional to t³/². The relation can be derived from the basic principles of work, energy, and motion in a system of force, velocity, and time.
Thus, the motion of the body shows how the distance traveled varies as a function of time when constant power is being delivered; it highlights the relationship between energy transfer and motion characteristics.
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The action and reaction forces referred to in Newtons third law
Action and reaction forces are equal in magnitude opposite in direction and act on different bodies. This question related to Chapter 4 physics Class 11th NCERT. From the Chapter 4 Laws of motion. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/Read more
Action and reaction forces are equal in magnitude opposite in direction and act on different bodies.
This question related to Chapter 4 physics Class 11th NCERT. From the Chapter 4 Laws of motion. Give answer according to your understanding.
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Which of the following quantities has the same direction as the net force?
According to Newton's second law, force causes acceleration in the same direction. This question related to Chapter 4 physics Class 11th NCERT. From the Chapter 4 Laws of motion. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/clRead more
According to Newton’s second law, force causes acceleration in the same direction. This question related to Chapter 4 physics Class 11th NCERT. From the Chapter 4 Laws of motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-4/