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The equation of the straight line which passes through the point (1, 2) and cuts off equal intercepts from the axes is
Choice (b) is correct. Let the intercepts on the axes be a and a respectively. The equation of the line is x/a + y/a = 1 ⇒ x + y = a Since the line passes through the point (1, 2), their coordinates must satisfy the equation (1). 1 + 2 = a ⇒ a = 3 Putting the value of a in (1), the equation of theRead more
Choice (b) is correct.
Let the intercepts on the axes be a and a respectively.
The equation of the line is x/a + y/a = 1 ⇒ x + y = a
Since the line passes through the point (1, 2), their coordinates must satisfy the equation (1).
1 + 2 = a ⇒ a = 3
Putting the value of a in (1), the equation of the line is x + y = 3.
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The slope of the straight line 2x – 7y = 13 is
Choice (d) is correct. The line is 2x - 7y = 13 Slope of the line, m = - coefficient of x / coefficient of y = -(2/-7) = 2/7 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more please visit here: httpsRead more
Choice (d) is correct.
The line is 2x – 7y = 13
Slope of the line, m = – coefficient of x / coefficient of y = -(2/-7) = 2/7
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The slope of the straight line, whose inclination with x-axis is 60° is
Choice (a) is correct. Here, θ = 60° Slope of the line = m = tan 60° = √3 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maRead more
Choice (a) is correct.
Here, θ = 60°
Slope of the line = m = tan 60° = √3
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The slope of the line perpendicular to the join of points A(3, 6) and B(9, -7) is
Choice (b) is correct. Slope of the line AB = m = y₂ - y ₁/x₂ - x₁= -7 - 6/9 - 3 = -13/6 Slope of the line perpendicular to line AB = -1/m = 6/13 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more pleaRead more
Choice (b) is correct.
Slope of the line AB = m = y₂ – y ₁/x₂ – x₁= -7 – 6/9 – 3 = -13/6
Slope of the line perpendicular to line AB = -1/m = 6/13
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The angle between x-axis and the line joining (3, -1) and (4, -2) is
Choice (c) is correct. Let the given points be P(3, -1) and Q(4, - 2). Slope of PQ = -2 + 1 /4 - 3 = -1/1 = -1 = m₁ and slope of x-axis = 0 = m₂ Let θ be the required angle between given lines. So, tan θ = m₂ - m₁ /1 + m₁m₂ = 0 + 1/1 - 0 = 1 ⇒ tan θ = tan 45° ⇒ θ = 45° This question related to ChapRead more
Choice (c) is correct.
Let the given points be P(3, -1) and Q(4, – 2).
Slope of PQ = -2 + 1 /4 – 3 = -1/1 = -1 = m₁
and slope of x-axis = 0 = m₂
Let θ be the required angle between given lines.
So, tan θ = m₂ – m₁ /1 + m₁m₂ = 0 + 1/1 – 0 = 1
⇒ tan θ = tan 45° ⇒ θ = 45°
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9