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A train moving with a velocity of 40m/s is brought to rest in 10 s. What is its acceleration?
Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 - 40/10 = -4m/s ² This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-soluRead more
Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 – 40/10 = -4m/s ²
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
Two particles A and B, initially at rest, move towards each other under mutual force of attraction. At the instant when the speed of A is v and the speed of B is 2v, the speed of the centre of mass of the system is
Two particles, A and B, start from rest, moving toward each other under mutual forces of attraction. In this case, the center of mass of the system continues to have zero speed. This is so because the system of two particles is isolated; no external forces are acting on it. In such systems, the motiRead more
Two particles, A and B, start from rest, moving toward each other under mutual forces of attraction. In this case, the center of mass of the system continues to have zero speed. This is so because the system of two particles is isolated; no external forces are acting on it. In such systems, the motion of the center of mass is determined only by external forces. Since there are none in this case, the center of mass remains stationary or maintains a constant velocity. Initially, both particles are at rest, so the velocity of the center of mass is zero.
As they move toward each other because of mutual attraction, their velocities change, but these changes are such that the internal forces do not affect the center of mass. Internal forces always act in equal and opposite directions, thus canceling out their effects on the system as a whole. Hence, even in the case of particle A travelling at speed v and particle B traveling at twice that speed (2v) the center of mass of this system does not gain any velocity to move. Such a scenario is in fact an exercise in the fundamental conservation of momentum concept in isolated systems.
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See lessWhat is the acceleration of a body moving with uniform velocity?
When a body moves with uniform velocity, its speed does not change over time. Since acceleration is the rate of change of velocity, it is zero for uniform velocity. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to yourRead more
When a body moves with uniform velocity, its speed does not change over time. Since acceleration is the rate of change of velocity, it is zero for uniform velocity.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
If a body’s velocity-time graph is a horizontal straight line, what can be inferred about the motion of the body?
A horizontal straight line in a velocity-time graph indicates that the velocity is constant. Therefore, the body is moving with uniform velocity. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. ForRead more
A horizontal straight line in a velocity-time graph indicates that the velocity is constant. Therefore, the body is moving with uniform velocity.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
A car travels 100 meters in 5 seconds. What is its average speed?
Average speed is calculated as Speed = Distance/Time. Substituting Distance = 100m and Time = 5s: Speed = 100/5 = 20m/s. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here:Read more
Average speed is calculated as Speed = Distance/Time. Substituting
Distance = 100m and Time = 5s:
Speed = 100/5 = 20m/s.
This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/