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  1. Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 - 40/10 = -4m/s ² This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-soluRead more

    Using a = v-u/t, where u = 40 m/s, v = 0m/s and t = 10s: a = 0 – 40/10 = -4m/s ²
    This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/

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  2. Two particles, A and B, start from rest, moving toward each other under mutual forces of attraction. In this case, the center of mass of the system continues to have zero speed. This is so because the system of two particles is isolated; no external forces are acting on it. In such systems, the motiRead more

    Two particles, A and B, start from rest, moving toward each other under mutual forces of attraction. In this case, the center of mass of the system continues to have zero speed. This is so because the system of two particles is isolated; no external forces are acting on it. In such systems, the motion of the center of mass is determined only by external forces. Since there are none in this case, the center of mass remains stationary or maintains a constant velocity. Initially, both particles are at rest, so the velocity of the center of mass is zero.

    As they move toward each other because of mutual attraction, their velocities change, but these changes are such that the internal forces do not affect the center of mass. Internal forces always act in equal and opposite directions, thus canceling out their effects on the system as a whole. Hence, even in the case of particle A travelling at speed v and particle B traveling at twice that speed (2v) the center of mass of this system does not gain any velocity to move. Such a scenario is in fact an exercise in the fundamental conservation of momentum concept in isolated systems.

    Click here for more:- https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/

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  3. When a body moves with uniform velocity, its speed does not change over time. Since acceleration is the rate of change of velocity, it is zero for uniform velocity. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to yourRead more

    When a body moves with uniform velocity, its speed does not change over time. Since acceleration is the rate of change of velocity, it is zero for uniform velocity.
    This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/

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  4. A horizontal straight line in a velocity-time graph indicates that the velocity is constant. Therefore, the body is moving with uniform velocity. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. ForRead more

    A horizontal straight line in a velocity-time graph indicates that the velocity is constant. Therefore, the body is moving with uniform velocity.
    This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/

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  5. Average speed is calculated as Speed = Distance/Time. Substituting Distance = 100m and Time = 5s: Speed = 100/5 = 20m/s. This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding. For more please visit here:Read more

    Average speed is calculated as Speed = Distance/Time. Substituting
    Distance = 100m and Time = 5s:
    Speed = 100/5 = 20m/s.
    This question related to Chapter 2 physics Class 11th NCERT. From the Chapter 2. Motion in Straight Line. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/

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