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If the net torque acting on a system is zero, what can we infer about the system’s angular momentum?
When net torque is zero, there is no change in angular momentum. According to the principle of conservation of angular momentum, 𝐿 = constant. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your undeRead more
When net torque is zero, there is no change in angular momentum. According to the principle of conservation of angular momentum, 𝐿 = constant. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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Write three distinct advantages of a reflecting type telescope over a refracting type telescope.
(i) No Chromatic Aberration: Reflecting telescopes avoid color distortions (chromatic aberration) since mirrors do not refract light. (ii) Larger Apertures: Mirrors can be made much larger than lenses, allowing for more light gathering. (iii) No Lens Sagging: Mirrors support their own weight, unlikeRead more
(i) No Chromatic Aberration: Reflecting telescopes avoid color distortions (chromatic aberration) since mirrors do not refract light.
(ii) Larger Apertures: Mirrors can be made much larger than lenses, allowing for more light gathering.
(iii) No Lens Sagging: Mirrors support their own weight, unlike lenses, which can sag and distort the image due to gravity.
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The decrease in the potential energy of a ball of mass 20 kg, which falls from a height 50 cm is
To determine the potential energy loss of a 20 kg ball dropped from 50 cm height, we shall use the potential energy formula: Potential Energy = mass × gravitational acceleration × height Mass (m) = 20 kg Height (h) = 50 cm = 0.5 m Gravitational acceleration (g) ≈ 9.8 m/s² Putting all these values inRead more
To determine the potential energy loss of a 20 kg ball dropped from 50 cm height, we shall use the potential energy formula:
Potential Energy = mass × gravitational acceleration × height
Mass (m) = 20 kg
Height (h) = 50 cm = 0.5 m
Gravitational acceleration (g) ≈ 9.8 m/s²
Putting all these values into the formula,
Potential Energy = 20 kg × 9.8 m/s² × 0.5 m
Potential Energy = 20 kg × 4.9 m²/s²
Potential Energy = 98 J
This implies that the potential energy of the ball has decreased by 98 J.
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This question examines the relationship between centripetal force and radius.
Centripetal force is 𝐹𝑐 =𝑚𝜔²𝑟. If 𝑟 is doubled, 𝐹𝑐 ∝ 𝑟, so the force becomes four times. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more please visit here: https://www.tiwRead more
Centripetal force is 𝐹𝑐 =𝑚𝜔²𝑟. If 𝑟 is doubled, 𝐹𝑐 ∝ 𝑟, so the force becomes four times. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
A body of mass 5 kg has momentum of 10 kg m s⁻¹. When a force of 0.2 N is applied on it for 10 s, what is the change in kinetic energy?
To find the change in kinetic energy of a body that has a mass of 5 kg and an initial momentum of 10 kg·m/s, we begin by finding the initial velocity. The definition of momentum as the product of mass and velocity reveals that the initial velocity is 2 m/s when calculated using the given mass and moRead more
To find the change in kinetic energy of a body that has a mass of 5 kg and an initial momentum of 10 kg·m/s, we begin by finding the initial velocity. The definition of momentum as the product of mass and velocity reveals that the initial velocity is 2 m/s when calculated using the given mass and momentum.
Next, we must know what the applied force does. For 10 s, a force of 0.2 N acts on the body. According to Newton’s second law, this will give an acceleration produced. Since we have the mass known, the computed acceleration is found to be 0.04 m/s².
Now, we could calculate the final velocity after a force has been applied. Acceleration increases this initial velocity of 2 m/s to a final velocity of 2.4 m/s.
We calculate the initial and final kinetic energies in order to determine the change in kinetic energy. The initial kinetic energy is 10 J, whereas the final kinetic energy, once the increase in velocity is considered, is 14.4 J. So, the change in kinetic energy is 4.4 J.
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