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What is the main purpose of Yoga?
The passage highlights Yoga as a journey of self-discovery, fostering holistic health by strengthening the body and calming the mind. It is portrayed as more than physical exercise—a profound science that helps individuals unlock their infinite potential. Through its practices, Yoga encourages balanRead more
The passage highlights Yoga as a journey of self-discovery, fostering holistic health by strengthening the body and calming the mind. It is portrayed as more than physical exercise—a profound science that helps individuals unlock their infinite potential. Through its practices, Yoga encourages balance, harmony, and inner peace, contributing to overall well-being. By incorporating its principles into daily life, practitioners can achieve self-realization, mindfulness, and a deeper connection with themselves and the world around them.
See lessThe kinetic energy of body of mass 2 kg and momentum of 2 N is
To calculate the kinetic energy of a body given its mass and momentum, we can make use of the relationship between momentum (p) and kinetic energy (K.E.). Step 1: Write the formulas - Momentum (p) is given by: p = mv - Kinetic energy (K.E.) is given by: K.E. = (1/2) mv² Step 2: Relate momentum to kiRead more
To calculate the kinetic energy of a body given its mass and momentum, we can make use of the relationship between momentum (p) and kinetic energy (K.E.).
Step 1: Write the formulas
– Momentum (p) is given by:
p = mv
– Kinetic energy (K.E.) is given by:
K.E. = (1/2) mv²
Step 2: Relate momentum to kinetic energy
We can write kinetic energy in terms of momentum:
Using the relation p = mv, we can rearrange to find v:
v = p/m
Substituting this into the kinetic energy formula:
K.E. = (1/2) m (p/m)²
K.E. = (1/2) (p²/m)
Step 3: Substitute the values
Given:
– Mass (m) = 2 kg
– Momentum (p) = 2 N·s (Note: momentum is in kg·m/s which is equivalent to N·s)
Now substituting into the formula for kinetic energy:
K.E. = (1/2) (p²/m)
K.E. = (1/2) [(2)² / 2]
K.E. = (1/2) [4 / 2]
K.E. = (1/2) [2]
K.E. = 1 J
Final Answer:
The kinetic energy of the body is 1 J.
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A body of mass 2 kg is placed on rough horizontal plane. The coefficient of friction between body and plane is 0.2 Then
To find the motion of the body placed on a rough horizontal plane, we need to consider the effects of friction and applied force. Given: Mass of the body (m) = 2 kg Coefficient of friction (μ) = 0.2 Acceleration due to gravity (g) = 9.8 m/s² (we will use 10 m/s² for simplicity) Step 1: Calculate theRead more
To find the motion of the body placed on a rough horizontal plane, we need to consider the effects of friction and applied force.
Given:
Mass of the body (m) = 2 kg
Coefficient of friction (μ) = 0.2
Acceleration due to gravity (g) = 9.8 m/s² (we will use 10 m/s² for simplicity)
Step 1: Calculate the normal force (N)
On a horizontal plane, the normal force (N) is equal to the weight of the body:
N = m * g
N = 2 kg * 10 m/s²
N = 20 N
Step 2: Find the maximum static friction (f_s)
The maximum static friction is given by:
f_s = μ * N
f_s = 0.2 * 20 N
f_s = 4 N
Step 3: Analyze the applied force (F)
Case (a): If F = 5 N
– The applied force (5 N) is greater than the maximum static friction (4 N).
– Hence, the body will move in the forward direction.
Case (b): If F = 3 N
– The applied force (3 N) is less than the maximum static friction (4 N).
– Thus, the body will not move and will remain at rest.
**Case (c):** If F = 3 N
– Since the applied force is not enough to overcome friction, the body will remain at rest.
Conclusion:
– For F = 5 N, the body will move in the forward direction.
– For F = 3 N, the body will remain at rest.
– Hence, both (a) and (c) are correct.
Final Answer:
The correct options are both (a) and (c).
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When a body moves with constant speed in a circular path, then
When a body is moving in a circular path with constant speed, we have to look into the consequences of circular motion. 1. Work done will be zero: - True. Since the force (centripetal force) is always perpendicular to the direction of motion, no work is done on the body. 2. Acceleration will be zeroRead more
When a body is moving in a circular path with constant speed, we have to look into the consequences of circular motion.
1. Work done will be zero:
– True. Since the force (centripetal force) is always perpendicular to the direction of motion, no work is done on the body.
2. Acceleration will be zero:
– False. The velocity has a constant speed but is changing direction all the time, and hence there is a centripetal acceleration directed toward the center of the circular path.
3. No force acts on the body:
– False. A net force (centripetal force) is necessary to keep the body moving in a circular path and is directed towards the center.
4. Its velocity remains constant:
– False. True, the velocity magnitude is unchanged, but the velocity is a vector: its direction must change; it is not a constant.
Final Answer:
Work done will be zero.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-5/
State one factor which determines the intensity of light in the photon nature of light.
In the photon nature of light, the intensity of light is determined by the number of photons incident per unit area per second. A higher photon count corresponds to greater energy delivery, thereby increasing the light's intensity. For more visit here: https://www.tiwariacademy.com/ncert-solutions/cRead more
In the photon nature of light, the intensity of light is determined by the number of photons incident per unit area per second. A higher photon count corresponds to greater energy delivery, thereby increasing the light’s intensity.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-11/