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Plot the points A (2, 1), B (–1, 2), C (–2, –1) and D (1, –2) in the coordinate plane. Is ABCD a square? Can you explain why? What is the area of this square?
By calculating the distances between the points, we find that all four sides are equal to the square root of 10 units. To confirm it is a square, we check the diagonals: both AC and BD are equal to the square root of 20 units. Since all sides are equal and both diagonals are equal, ABCD is a perfectRead more
By calculating the distances between the points, we find that all four sides are equal to the square root of 10 units. To confirm it is a square, we check the diagonals: both AC and BD are equal to the square root of 20 units. Since all sides are equal and both diagonals are equal, ABCD is a perfect square. The area is calculated by squaring the side length, which gives a total of 10 square units.
For Detailed Solutions:
Visit NCERT Solutions for Class 9 Ganita Manjari Chapter 1 Orienting Yourself: The Use of Coordinates Question Answer:
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-1/
See lessNCERT solutions for class 9 Sanskrit Sharada for 2026-27
NCERT Solutions for Class 9 Sanskrit Sharada (2026–27) provide detailed, chapter-wise answers according to the latest NCERT syllabus and NEP 2020 guidelines. These solutions cover all sixteen chapters with clear explanations of grammar, word meanings and exercises. With simple language and accurateRead more
NCERT Solutions for Class 9 Sanskrit Sharada (2026–27) provide detailed, chapter-wise answers according to the latest NCERT syllabus and NEP 2020 guidelines. These solutions cover all sixteen chapters with clear explanations of grammar, word meanings and exercises. With simple language and accurate solutions, students can achieve better academic performance in new Class 9 Sanskrit Sharada book (संस्कृत शारदा).
Class 9 NCERT/CBSE New book Sanskrit Sharada Chapter List:
Chapter 1 – सत्यं शिवं सुन्दरं संस्कृतम्
Chapter 2 – सुखस्य मूलं धर्म: धर्मस्य मूलम् अर्थ:
Chapter 3 – आत्मवत्सर्वभूतेषु यः पश्यति सः पण्डितः
Chapter 4 – न खलु वयस्तेजसो हेतुः
Chapter 5 – एषा सा कृतकबुद्धि: मानवबुद्ध: सहकरी
Chapter 6 – मनःपूतं समाचरेत
Chapter 7 – उपायं चिन्तयेत प्राज्ञस्तथापायं च चिन्तयेत
Chapter 8 – अन्नाद् आनन्दं प्रति
Chapter 9 – कृतं प्रतिकृतं भूयादेष धर्मः सनातनः
Chapter 10 – णमो अरिहन्ताणम्
Chapter 11 – वर्णोच्चारण-शिक्षा २
Chapter 12 – अन्वयः
Chapter 13 – समासः
Chapter 14 – वाच्यम्
Chapter 15 – शब्दरूपाणि
Chapter 16 – धातुरूपाणि
For more NCERT Solutions of Class 9 Sanskrit Sharada (संस्कृत शारदा) All Chapter Solutions (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/sanskrit/
See lessWhat are the coordinates of D1?
Based on the grid layout, point D1 is located on the horizontal axis. We determine its position by counting 9 units from the origin along the North-South/East-West grid lines as described in the text. Since D1 lies exactly on the x-axis, its vertical position or y-coordinate is 0. Therefore, the exaRead more
Based on the grid layout, point D1 is located on the horizontal axis. We determine its position by counting 9 units from the origin along the North-South/East-West grid lines as described in the text. Since D1 lies exactly on the x-axis, its vertical position or y-coordinate is 0. Therefore, the exact coordinates of D1 are written as (9, 0), representing its horizontal and vertical distances respectively.
For Detailed Solutions:
Visit NCERT Solutions for Class 9 Ganita Manjari Chapter 1 Orienting Yourself: The Use of Coordinates Question Answer:
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-1/
See lessIf B1 (0, 1.5) and B2 (0, 4) represent the ends of the bathroom door, is the bathroom door narrower or wider than the room door?
To compare the doors, we calculate their lengths. The room door width is 2.5 units (11.5 minus 9). The bathroom door lies on the y-axis, so we subtract its y-coordinates: 4 minus 1.5 equals 2.5 units. Since both calculations result in a distance of 2.5 units, the bathroom door is neither narrower noRead more
To compare the doors, we calculate their lengths. The room door width is 2.5 units (11.5 minus 9). The bathroom door lies on the y-axis, so we subtract its y-coordinates: 4 minus 1.5 equals 2.5 units. Since both calculations result in a distance of 2.5 units, the bathroom door is neither narrower nor wider; both the room door and the bathroom door are equal in width.
For Detailed Solutions:
Visit NCERT Solutions for Class 9 Ganita Manjari Chapter 1 Orienting Yourself: The Use of Coordinates Question Answer:
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-1/
See lessIf R1 is the point (11.5, 0), how wide is the door? Do you think this is a comfortable width for the room door? If a person in a wheelchair wants to enter the room, will he/she be able to do so easily?
The width is calculated by subtracting the x-coordinates: 11.5 minus 9 equals 2.5 units. If we assume a standard scale where 1 unit equals 20 cm, the width is 50 cm. This is generally considered uncomfortable for a main room door. Specifically, a standard wheelchair requires a minimum width of aboutRead more
The width is calculated by subtracting the x-coordinates: 11.5 minus 9 equals 2.5 units. If we assume a standard scale where 1 unit equals 20 cm, the width is 50 cm. This is generally considered uncomfortable for a main room door. Specifically, a standard wheelchair requires a minimum width of about 80 to 90 cm to pass through easily. Therefore, a person in a wheelchair would not be able to enter easily.
For Detailed Solutions:
Visit NCERT Solutions for Class 9 Ganita Manjari Chapter 1 Orienting Yourself: The Use of Coordinates Question Answer:
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-1/
See less