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What will you do differently next time?
In future projects, I will prioritize selecting plants that thrive in the local climate and prepare organic pesticides in advance to manage pests effectively. I will plan a more structured watering and maintenance schedule to ensure consistent care. Creating a detailed timeline for each activity wilRead more
In future projects, I will prioritize selecting plants that thrive in the local climate and prepare organic pesticides in advance to manage pests effectively. I will plan a more structured watering and maintenance schedule to ensure consistent care. Creating a detailed timeline for each activity will improve overall efficiency. Additionally, I will explore eco-friendly practices, like mulching and composting, to enrich the soil and promote healthy plant growth while minimizing external resource use.
See lessWhat were the challenges that you faced during the activities?
The main challenges involved controlling pests that harmed the plants, managing a consistent watering schedule, and maintaining soil health. Limited access to some required tools and materials added complexity to the process. Adapting to sudden weather changes, such as heavy rain or heatwaves, requiRead more
The main challenges involved controlling pests that harmed the plants, managing a consistent watering schedule, and maintaining soil health. Limited access to some required tools and materials added complexity to the process. Adapting to sudden weather changes, such as heavy rain or heatwaves, required protective measures like using covers or relocating pots. Balancing time between gardening and other tasks was another hurdle. These challenges provided valuable learning opportunities for future gardening activities.
See lessThe sun emits a light with maximum wavelength 510 nm, while another star X emits a light with maximum wavelength of 350nm. What is the ratio surface temperature of the sun and the star X?
To calculate the ratio of the surface temperatures of the Sun and star X, we use Wien’s displacement law: λ_max × T = b where: - λ_max is the wavelength at maximum radiation, - T is the temperature of the object, - b is Wien's constant (2.9 × 10⁶ nm·K). The ratio of the temperatures is given by: (T_Read more
To calculate the ratio of the surface temperatures of the Sun and star X, we use Wien’s displacement law:
λ_max × T = b
where:
– λ_max is the wavelength at maximum radiation,
– T is the temperature of the object,
– b is Wien’s constant (2.9 × 10⁶ nm·K).
The ratio of the temperatures is given by:
(T_sun / T_star_X) = λ_max_star_X / λ_max_sun
Substitute the given values:
– λ_max_sun = 510 nm,
– λ_max_star_X = 350 nm.
(T_sun / T_star_X) = 350 / 510 = 0.686
Thus, the ratio of surface temperatures is approximately 0.68.
The correct answer is 0.68.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-10/
Suppose the sun expands so that its radius becomes 100 times its present radius and its surface temperature becomes half of its present value. The total energy emitted by it then will increase by a factor of
We can apply the Stefan-Boltzmann law to compute the change in the total energy emitted: E = σ T⁴ A Here, - E is the total energy emitted - σ is the Stefan-Boltzmann constant - T is the surface temperature - A is the surface area of the object Surface area of sphere is given as: A = 4π r² If the radRead more
We can apply the Stefan-Boltzmann law to compute the change in the total energy emitted:
E = σ T⁴ A
Here,
– E is the total energy emitted
– σ is the Stefan-Boltzmann constant
– T is the surface temperature
– A is the surface area of the object
Surface area of sphere is given as:
A = 4π r²
If the radius of the sun increases by a factor of 100 and the temperature decreases by half, we need to calculate the change in energy.
Let the initial energy be E₁, and the final energy be E₂.
Initial energy: E₁ = σ T₁⁴ (4π r₁²)
Final energy: E₂ = σ (T₁/2)⁴ (4π (100r₁)²)
Simplifying the ratio of the final energy to the initial energy:
(E₂ / E₁) = (T₁/2)⁴ (100²) = (1/16) (10000) = 625
Thus, the total energy emitted increases by a factor of 625.
The correct answer is 625.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-10/
A black body at a high temperature T K radiates energy at the rate of E Wm⁻². When the temperature falls to T/2 K, the radiated energy will be
According to the Stefan-Boltzmann law, the energy radiated by a black body is given by: E = σ T⁴ where: - E is the radiated energy, - σ is the Stefan-Boltzmann constant, - T is the temperature in Kelvin. Now, when the temperature is reduced to T/2, the new energy radiated will be: E' = σ (T/2)⁴ = (σRead more
According to the Stefan-Boltzmann law, the energy radiated by a black body is given by:
E = σ T⁴
where:
– E is the radiated energy,
– σ is the Stefan-Boltzmann constant,
– T is the temperature in Kelvin.
Now, when the temperature is reduced to T/2, the new energy radiated will be:
E’ = σ (T/2)⁴ = (σ T⁴) / 16
So the radiated energy decreases by a factor of 16, meaning the new radiated energy is E/16.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-10/