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Solids, liquids and gases differ from each other in terms of (a) arrangement of particles. (b) attractive forces between the particles. (c) spaces between the particles. (d) all of these.
(d) All the options are correct. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(d) All the options are correct.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
See lessChemically, dry ice is (a) solid SO₂ (b) solid NO₂ (c) solid CO₂ (d) solid H₂
(c) Solid CO2 is called dry ice because it does not wet on evaporation and directly changes into vapours. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(c) Solid CO2 is called dry ice because it does not wet on evaporation and directly changes into vapours.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
See lessThe area of curve xy = 4, bounded by the lines x =1 and x = 3 and x-axis in sq. units is
Determine the area of the region bounded by the curve xy = 4 and the lines x = 1, x = 3, and the x-axis. First we rewrite the equation xy = 4 to solve for y in terms of x. Now solving the above equation for y we get, y = 4/x Step 1 We begin by setting up the integral The area can be calculated by inRead more
Determine the area of the region bounded by the curve xy = 4 and the lines x = 1, x = 3, and the x-axis. First we rewrite the equation xy = 4 to solve for y in terms of x.
Now solving the above equation for y we get,
y = 4/x
Step 1
We begin by setting up the integral
The area can be calculated by integrating y = 4/x from x = 1 to x = 3:
A = ∫₁³ (4/x) dx
Step 2: Evaluate the integral
We know that:
∫ (1/x) dx = ln |x|
Thus, the integral becomes:
A = 4 ∫₁³ (1/x) dx = 4 [ln x]₁³
Step 3: Calculate the area
At x = 3:
ln 3
At x = 1:
ln 1 = 0
Therefore, the area is
A = 4 (ln 3 – 0) = 4 ln 3
Using logarithmic properties:
A = ln (3⁴) = ln 81
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-8
he area bounded by the curve y = sin x, x – axis, ordinates x = 0 and x = 2x is
To find the area bounded by the curve y = sin x, the x-axis, and the ordinates x = 0 and x = 2, we must calculate the definite integral of sin x from 0 to 2. Step 1: Set up the integral The area is given by: A = ∫₀² sin x dx Step 2: Solve the integral We know the integral of sin x is: ∫ sin x dx = -Read more
To find the area bounded by the curve y = sin x, the x-axis, and the ordinates x = 0 and x = 2, we must calculate the definite integral of sin x from 0 to 2.
Step 1: Set up the integral
The area is given by:
A = ∫₀² sin x dx
Step 2: Solve the integral
We know the integral of sin x is:
∫ sin x dx = -cos x
Now, evaluate the integral from 0 to 2:
A = [-cos x]₀²
At x = 2:
-cos(2)
At x = 0:
-cos(0) = -1
Thus, the area is:
A = -cos(2) – (-1) = 1 + cos(2)
Step 3: Approximate the result
Using a calculator, cos(2) ≈ -0.416, so:
A ≈ 1 – (-0.416) = 1 + 0.416 = 1.416
Thus, the closest option to this result is: 4/3 sq. units.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-8
Choose the correct statement out of the following: ( a) Conversion of solid into vapours without passing through the liquid state is called sublimation. (b) Conversion of vapours into solid without passing through the liquid state is called sublimation. (c) Conversion of vapours into solid without passing through the liquid state is called freezing. (d) Conversion of solid into liquid is called sublimation.
(a) Conversion of solid into vapours without passing through the liquid state is called sublimation. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(a) Conversion of solid into vapours without passing through the liquid state is called sublimation.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
See less