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  1. We have to calculate the definite integral of sin x from 0 to 2π in order to find the area bounded by the curve y = sin x, the x-axis, and the ordinates x = 0 and x = 2π. Step 1: Setup the integral The area is given by: A = ∫₀²π sin x dx Step 2: Solve the integral We know the integral of sin x is ∫Read more

    We have to calculate the definite integral of sin x from 0 to 2π in order to find the area bounded by the curve y = sin x, the x-axis, and the ordinates x = 0 and x = 2π.

    Step 1: Setup the integral
    The area is given by:
    A = ∫₀²π sin x dx

    Step 2: Solve the integral
    We know the integral of sin x is

    ∫ sin x dx = -cos x

    Evaluate the integral from 0 to 2π:

    A = [-cos x]₀²π

    At x = 2π:

    -cos(2π) = -1

    At x = 0:

    -cos(0) = -1

    Hence, area is:

    A = -1 – (-1) = 0

    Since sin x is above the x-axis for the interval [0, π] and below the x-axis for the interval [π, 2π], the areas of these two parts are equal in magnitude but opposite in sign. So we take the absolute value of the integrals over both intervals.

    Step 3: Evaluate the area with absolute value
    Area =

    A = 2 × ∫₀π sin x dx = 2 [-cos x]₀π

    At x = π:

    -cos(π) = 1

    At x = 0:

    -cos(0) = -1

    Thus, the area is: A = 2 × (1 – (-1)) = 2 × 2 = 4

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    https://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-8

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