Share & grow the world's knowledge!
We want to connect the people who have knowledge to the people who need it, to bring together people with different perspectives so they can understand each other better, and to empower everyone to share their knowledge.
Distance of the point (p, q, r) from y-axis is
Three-dimensional space is defined by x = 0 and z = 0 which forms the y-axis. The distance of a point (p, q, r) from the y-axis is computed by its x and z coordinates because the y-axis does not have any displacement in the x or z direction. Therefore, the distance is the perpendicular distance of tRead more
Three-dimensional space is defined by x = 0 and z = 0 which forms the y-axis.
The distance of a point (p, q, r) from the y-axis is computed by its x and z coordinates because the y-axis does not have any displacement in the x or z direction.
Therefore, the distance is the perpendicular distance of the point from the yaxis, that is given by
√(p² + r²)
So, the correct answer is: √(p² + r²)
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-11
In school 500 students like coffee an 300 students like juice and 120 students like both coffee and juice. Then the students liking coffee or juice is
Choice (c) is correct. Let A and B the sets of students liking coffee and juice respectively. n(A) = 500, n(B) = 300 and n(A ∩ B) = 120 Number of students liking coffee or juice = n (A ∪ B) = n(A) +n(B) - n(A ∩ B) = 500 + 300 - 120 = 680 This question related to Chapter 1 maths Class 11th NCERT. FRead more
Choice (c) is correct.
Let A and B the sets of students liking coffee and juice respectively.
n(A) = 500, n(B) = 300 and n(A ∩ B) = 120
Number of students liking coffee or juice = n (A ∪ B) = n(A) +n(B) – n(A ∩ B) = 500 + 300 – 120 = 680
This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-1
Equation of a line passing through point (1, 1, 1) and parallel to z-axis is
A line parallel to the z-axis has constant x and y coordinates, while the z-coordinate changes. For a line passing through the point (1, 1, 1) and parallel to the z-axis, the x and y coordinates remain constant at 1, while the z-coordinate changes. The parametric equation of the line is: (x - 1)/0 =Read more
A line parallel to the z-axis has constant x and y coordinates, while the z-coordinate changes. For a line passing through the point (1, 1, 1) and parallel to the z-axis, the x and y coordinates remain constant at 1, while the z-coordinate changes.
The parametric equation of the line is:
(x – 1)/0 = (y – 1)/0 = (z – 1)/1
Thus, the correct answer is:
(x – 1)/0 = (y – 1)/0 = (z – 1)/1
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-11
If n(A) = 10, n (B) = 6, n(C) = 5 for three disjoints sets A, B and C, then n (A ∪ B ∪ C) =
Choice (a). is correct. As A, B and C are disjoints sets. n(A ∪ B ∪ C) = n (A) +n(B) +n(C) = 10 + 6 + 5 = 21 This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/nceRead more
Choice (a). is correct. As A, B and C are disjoints sets. n(A ∪ B ∪ C) = n (A) +n(B) +n(C) = 10 + 6 + 5 = 21
This question related to Chapter 1 maths Class 11th NCERT. From the Chapter 1. Sets. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-1
The angle between the lines 2x = 3y = -z and 6x = -y = -4z is
The given equations of the lines can be written in parametric form: For the first line: 2x = 3y = -z, let the parameter be t. x = t/2, y = t/3, z = -t. For the second line: 6x = -y = -4z, let the parameter be s. x = s/6, y = -s, z = -s/4. The direction ratios of the first line are (1/2, 1/3, -1) andRead more
The given equations of the lines can be written in parametric form:
For the first line:
2x = 3y = -z, let the parameter be t.
x = t/2, y = t/3, z = -t.
For the second line:
6x = -y = -4z, let the parameter be s.
x = s/6, y = -s, z = -s/4.
The direction ratios of the first line are (1/2, 1/3, -1) and the direction ratios of the second line are (1/6, -1, -1/4).
The angle θ between two lines is given by the formula:
cos θ = (l₁l₂ + m₁m₂ + n₁n₂) / √(l₁² + m₁² + n₁²) * √(l₂² + m₂² + n₂²)
Substitute the values:
cos θ = [(1/2)(1/6) + (1/3)(-1) + (-1)(-1/4)] / √[(1/2)² + (1/3)² + (-1)²] * √[(1/6)² + (-1)² + (-1/4)²]
Simplifying this expression results in cos θ = 0, so the angle θ = 90°.
Thus, the correct answer is: 90°
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-11