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The value of 64 π is
Choice (c) is correct. sin 64 π = sin (2π × 32 + 0) = sin 0 = 0 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/matRead more
Choice (c) is correct.
sin 64 π = sin (2π × 32 + 0) = sin 0 = 0
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
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The value of tan 1° tan 2° tan 3° ….. tan89° is equal to
Choice (b) is correct tan 1° tan 2° tan 3° ..... tan89° = (tan 1° tan89°) (tan 2° tan 88°)....(tan 44° tan 46°) tan 45° = {tan 1° tan (90° - 1°)} {tan 2° tan (90° - 2°)}..... {tan 44° tan (90° - 44°)} tan 45° = (tan 1° cot 1°) (tan 2° cot 2°).... (tan 44° cot 44°) tan45° = (1) (1)...(1)(1) = 1 ThisRead more
Choice (b) is correct tan 1° tan 2° tan 3° ….. tan89° = (tan 1° tan89°) (tan 2° tan 88°)….(tan 44° tan 46°) tan 45°
= {tan 1° tan (90° – 1°)} {tan 2° tan (90° – 2°)}….. {tan 44° tan (90° – 44°)} tan 45°
= (tan 1° cot 1°) (tan 2° cot 2°)…. (tan 44° cot 44°) tan45°
= (1) (1)…(1)(1) = 1
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
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If the corner points of the feasible region of an LPP are (0, 3), (3, 2) and (0, 5), then the minimum value of Z = 11x 7 y is
To find the minimum value of Z = 11x + 7y, we substitute the corner points of the feasible region into the equation. For point (0, 3), Z = 11(0) + 7(3) = 21. For point (3, 2), Z = 11(3) + 7(2) = 33. For point (0, 5), Z = 11(0) + 7(5) = 35. Thus, the minimum value of Z is 21 at the point (0, 3). ClicRead more
To find the minimum value of Z = 11x + 7y, we substitute the corner points of the feasible region into the equation.
For point (0, 3), Z = 11(0) + 7(3) = 21.
For point (3, 2), Z = 11(3) + 7(2) = 33.
For point (0, 5), Z = 11(0) + 7(5) = 35.
Thus, the minimum value of Z is 21 at the point (0, 3).
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Variable of the objective function of the linear programming problem are
"Objective function". In linear programming, the objective function is a function that must be optimized - either maximized or minimized. The variables of the objective function are the decision variables we seek to determine to achieve an optimal solution. Click for more: https://www.tiwariacademy.Read more
“Objective function”. In linear programming, the objective function is a function that must be optimized – either maximized or minimized. The variables of the objective function are the decision variables we seek to determine to achieve an optimal solution.
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The point which does not lie in the half – plane 2x + 3y -12 ≤ 0 is
In order to see which point is not in the half-plane 2x + 3y - 12 ≤ 0, we put in the coordinates for each point in the inequality. 1. Point (1, 2) 2(1) + 3(2) - 12 = 2 + 6 - 12 = -4 ≤ 0. The point (1, 2) is in the half-plane. 2. Point (2, 1) 2(2) + 3(1) - 12 = 4 + 3 - 12 = -5 ≤ 0. Point (2, 1) liesRead more
In order to see which point is not in the half-plane 2x + 3y – 12 ≤ 0, we put in the coordinates for each point in the inequality.
1. Point (1, 2)
2(1) + 3(2) – 12 = 2 + 6 – 12 = -4 ≤ 0. The point (1, 2) is in the half-plane.
2. Point (2, 1)
2(2) + 3(1) – 12 = 4 + 3 – 12 = -5 ≤ 0. Point (2, 1) lies in the half-plane.
3. For point (2, 3):
2(2) + 3(3) – 12 = 4 + 9 – 12 = 1 > 0. Point (2, 3) does NOT lie in the half-plane.
4. For point (-3, 2):
2(-3) + 3(2) – 12 = -6 + 6 – 12 = -12 ≤ 0. Point (-3, 2) lies in the half-plane.
Thus, the point which does not lie in the half-plane is (2, 3).
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