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If tan θ = 3 and θ lies in third quadrant, then the value of sin θ is
Choice (d) is correct. Given that , tan θ = 3 we know that, sec² θ = 1 + tan² θ ⇒ sec² θ = 1 + 3² = 1 + 9 = 10 ⇒ cos² θ = 1/10 We know that sin² θ = 1 - cos² θ sin² θ = 1 - 1/10 = 10 - 1/10 = 9/10 ⇒ sin θ = ± √9/10 = ± 3/√10 ⇒ sin θ = -3√10 This question related to Chapter 3 maths Class 11th NCERT.Read more
Choice (d) is correct. Given that , tan θ = 3
we know that, sec² θ = 1 + tan² θ
⇒ sec² θ = 1 + 3² = 1 + 9 = 10 ⇒ cos² θ = 1/10
We know that sin² θ = 1 – cos² θ
sin² θ = 1 – 1/10 = 10 – 1/10 = 9/10
⇒ sin θ = ± √9/10 = ± 3/√10 ⇒ sin θ = -3√10
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
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Which of the following is correct?
Choice (b) is correct. We know that sine function is an increasing function in first quadrant and 1 radian = 57.296 degrees. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit hereRead more
Choice (b) is correct. We know that sine function is an increasing function in first quadrant and 1 radian = 57.296 degrees. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
If f(x) = cos² x + sec ² x, then
Choice (a) is correct. Given that, f(x) = cos² x + sec² x We know that, A.M ≥ G.M (cos² x + sec ² x)/2 ≥ √cos² x. sec ² x ⇒ cos² x + sec ² x ≥ 2 ⇒ f(x) ≥ 2 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understaRead more
Choice (a) is correct.
Given that, f(x) = cos² x + sec² x
We know that, A.M ≥ G.M
(cos² x + sec ² x)/2 ≥ √cos² x. sec ² x
⇒ cos² x + sec ² x ≥ 2
⇒ f(x) ≥ 2
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
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The value of cos 25° 35′ cos34° 25′ – sin 25° 34′ sin 34°’ 25′ is
Choice (d) is correct. cos 25° 35' cos 34° 25' - sin25° 35' sin 34°' 25' = cos(25° 35' + 34° 25') = cos 60° = 1/2 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://wRead more
Choice (d) is correct.
cos 25° 35′ cos 34° 25′ – sin25° 35′ sin 34°’ 25′ = cos(25° 35′ + 34° 25′) = cos 60° = 1/2
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
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Period of cosecant function is
Choice (a) is correct. Period of cosecant function 2π. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chaptRead more
Choice (a) is correct.
Period of cosecant function 2π. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3