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The slope of the line perpendicular to the join of points A(3, 6) and B(9, -7) is
Choice (b) is correct. Slope of the line AB = m = y₂ - y ₁/x₂ - x₁= -7 - 6/9 - 3 = -13/6 Slope of the line perpendicular to line AB = -1/m = 6/13 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more pleaRead more
Choice (b) is correct.
Slope of the line AB = m = y₂ – y ₁/x₂ – x₁= -7 – 6/9 – 3 = -13/6
Slope of the line perpendicular to line AB = -1/m = 6/13
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
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The angle between x-axis and the line joining (3, -1) and (4, -2) is
Choice (c) is correct. Let the given points be P(3, -1) and Q(4, - 2). Slope of PQ = -2 + 1 /4 - 3 = -1/1 = -1 = m₁ and slope of x-axis = 0 = m₂ Let θ be the required angle between given lines. So, tan θ = m₂ - m₁ /1 + m₁m₂ = 0 + 1/1 - 0 = 1 ⇒ tan θ = tan 45° ⇒ θ = 45° This question related to ChapRead more
Choice (c) is correct.
Let the given points be P(3, -1) and Q(4, – 2).
Slope of PQ = -2 + 1 /4 – 3 = -1/1 = -1 = m₁
and slope of x-axis = 0 = m₂
Let θ be the required angle between given lines.
So, tan θ = m₂ – m₁ /1 + m₁m₂ = 0 + 1/1 – 0 = 1
⇒ tan θ = tan 45° ⇒ θ = 45°
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The intercepts cut by the line 3x + 5y = 15 on the x-axis and the y-axis are
Choice (b) is correct. Putting y = 0 in the equation, we get 3x = 15 i.e., x = 5 ⇒ Intercept on x-axis = 5 Putting x = 0 in the equation, we get 5y = 15 i.e., y = 3 ⇒ Intercept on y-axis = 3 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer aRead more
Choice (b) is correct.
Putting y = 0 in the equation, we get 3x = 15 i.e., x = 5 ⇒ Intercept on x-axis = 5
Putting x = 0 in the equation, we get 5y = 15 i.e., y = 3 ⇒ Intercept on y-axis = 3
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The equation of the straight line passing through the point (2, -3) and parallel to the x-axis is
Choice (b) is correct. The equation of any line parallel to the x-axis is y = k If it passes through the point (2, -3), then its coordinates must satisfy its equation -3 = k Putting the value of k, the equation of the required line is y = -3 This question related to Chapter 9 maths Class 11th NCERT.Read more
Choice (b) is correct.
The equation of any line parallel to the x-axis is y = k
If it passes through the point (2, -3), then its coordinates must satisfy its equation -3 = k
Putting the value of k, the equation of the required line is y = -3
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
If x, y and z are distinct positive integers, then value of expression (x + y) (y + z) (z + x) is
Choice (b) is correct. We know that in case of distinct numbers A.M. > G.M x + y /2 > √xy, y + z/2 >√yz and z + x /2 >√zx Multiplying above three inequalities, we get x + y/2 . y + z /2 . z + x /2 >√xy. √yz. √zx ⇒ (x + y) (y + z) (z + x) >8xyz For more please visit here: https:/Read more
Choice (b) is correct.
We know that in case of distinct numbers A.M. > G.M
x + y /2 > √xy, y + z/2 >√yz and z + x /2 >√zx
Multiplying above three inequalities, we get
x + y/2 . y + z /2 . z + x /2 >√xy. √yz. √zx
⇒ (x + y) (y + z) (z + x) >8xyz
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-8