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The tops of two poles of height 16m and 10m are connected by a wire of length l metres. If the wire makes an angle of 30° with the horizontal, then l =
We are given: Height of the first pole = 16 m, Height of the second pole = 10 m, The wire makes an angle of 30° with the horizontal. Find the vertical difference between the tops of the poles The vertical difference between the tops of the two poles is: 16 - 10 = 6 m. Step 2: Use the sine functionRead more
We are given:
Height of the first pole = 16 m,
Height of the second pole = 10 m,
The wire makes an angle of 30° with the horizontal.
Find the vertical difference between the tops of the poles
The vertical difference between the tops of the two poles is:
16 – 10 = 6 m.
Step 2: Use the sine function
The wire forms the hypotenuse of a right triangle, where:
The vertical difference (6 m) is the opposite side,
The angle between the wire and the horizontal is 30°.
Using the sine function:
sinθ = (Opposite side) / (Hypotenuse).
Substitute the values:
sin30° = 6 / l.
From trigonometric values, sin30° = 1/2:
1/2 = 6 / l.
Solve for l
Multiply through by l:
l × (1/2) = 6.
Simplify:
l = 6 × 2 = 12 m
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/
What did you enjoy doing during the activity?
I thoroughly enjoyed the entire cooking activity, especially the process of mixing ingredients and balancing flavors to create a delicious dish. The creative freedom to experiment with combinations and the fun of presenting the dish in an attractive way made it even more enjoyable. Working with my tRead more
I thoroughly enjoyed the entire cooking activity, especially the process of mixing ingredients and balancing flavors to create a delicious dish. The creative freedom to experiment with combinations and the fun of presenting the dish in an attractive way made it even more enjoyable. Working with my team was another highlight, as we shared ideas, solved problems together and encouraged one another. The sense of accomplishment after seeing the final dish was incredibly satisfying and rewarding.
See lessIt is found that on walking x meters towards a chimney in a horizontal line through its base, the elevation of its top changes from 30° to 60°. The height of the chimney is
Given: - Angle of elevation changes from 30° to 60° as we walk x meters towards the chimney. Using tangent for both angles: 1. tan30° = h / d ⇒ d = h√3. 2. tan60° = h / (d - x) ⇒ d - x = h / √3. Substitute d = h√3 into d - x = h / √3: h√3 - x = h / √3. Simplify: x = h√3 - h / √3 = (2h) / √3. Solve fRead more
Given:
– Angle of elevation changes from 30° to 60° as we walk x meters towards the chimney.
Using tangent for both angles:
1. tan30° = h / d ⇒ d = h√3.
2. tan60° = h / (d – x) ⇒ d – x = h / √3.
Substitute d = h√3 into d – x = h / √3:
h√3 – x = h / √3.
Simplify:
x = h√3 – h / √3 = (2h) / √3.
Solve for h:
h = (√3 / 2) x.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/
The tops of two poles of height 20m and 14 m are connect by a wire. If the wire makes an angle of 30° with horizontal, then the length of the wire is
Given: Height of the first pole = 20m, Height of the second pole = 14m, Angle of the wire with the horizontal = 30°. Find the vertical difference Vertical difference = 20 - 14 = 6m. Use the sine function sinθ = (Vertical difference) / (Length of the wire). sin30° = 6 / L. From trigonometric values,Read more
Given:
Height of the first pole = 20m,
Height of the second pole = 14m,
Angle of the wire with the horizontal = 30°.
Find the vertical difference
Vertical difference = 20 – 14 = 6m.
Use the sine function
sinθ = (Vertical difference) / (Length of the wire).
sin30° = 6 / L.
From trigonometric values, sin30° = 1/2:
1/2 = 6 / L.
Solve for L
L = 6 × 2 = 12m.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/
If the angle of elevation of a cloud from a point 200m above a lake is 30° and the angle of depression of its reflection in the lake is 60°, then the height of the cloud above the lake, is
Given: - Observer is 200m above the lake. - Angle of elevation of cloud = 30°. - Angle of depression of reflection = 60°. Using tangent for both angles: 1. tan30° = (h - 200) / d ⇒ d = √3(h - 200). 2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d. Substitute d = √3(h - 200) into the second equation: √Read more
Given:
– Observer is 200m above the lake.
– Angle of elevation of cloud = 30°.
– Angle of depression of reflection = 60°.
Using tangent for both angles:
1. tan30° = (h – 200) / d ⇒ d = √3(h – 200).
2. tan60° = (h + 200) / d ⇒ √3 = (h + 200) / d.
Substitute d = √3(h – 200) into the second equation:
√3 = (h + 200) / (√3(h – 200)).
Simplify:
3(h – 200) = h + 200.
Solve for h:
2h = 800 ⇒ h = 400.
This question related to Chapter 9 Mathematics Class 10th NCERT. From the Chapter 9 Applications of Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions/class-10/maths/