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When a conductor is held in an electric field, the field inside the conductor is always
The correct answer is (d) zero. When a conductor is placed in an electric field, free electrons within it redistribute to cancel the external field inside. This results in electrostatic equilibrium, where the net electric field inside the conductor becomes zero. This phenomenon ensures no electric fRead more
The correct answer is (d) zero.
When a conductor is placed in an electric field, free electrons within it redistribute to cancel the external field inside. This results in electrostatic equilibrium, where the net electric field inside the conductor becomes zero. This phenomenon ensures no electric force acts on charges within the conductor.
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For 0° ≤ θ < 90°, the maximum value of 1/secθ is
We are tasked with finding the maximum value of 1/secθ for 0° ≤ θ < 90°. Step 1: Recall the definition of secant The secant function is defined as: secθ = 1/cosθ. Thus, the reciprocal of secant is: 1/secθ = cosθ. Step 2: Analyze the behavior of cosθ in the given range For 0° ≤ θ < 90°: - The cRead more
We are tasked with finding the maximum value of 1/secθ for 0° ≤ θ < 90°.
Step 1: Recall the definition of secant
The secant function is defined as:
secθ = 1/cosθ.
Thus, the reciprocal of secant is:
1/secθ = cosθ.
Step 2: Analyze the behavior of cosθ in the given range
For 0° ≤ θ < 90°:
– The cosine function decreases from cos 0° = 1 to cos 90° = 0 (but does not actually reach 0 since θ < 90°).
– Therefore, the maximum value of cosθ occurs at θ = 0°.
At θ = 0°:
cos 0° = 1.
Step 3: Conclusion
The maximum value of 1/secθ is equal to the maximum value of cosθ, which is 1.
The correct answer is:
a) 1
This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.
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sin 2A = 2 sinA is true when A =
We are given the equation: sin 2A = 2 sin A. Step 1: Recall the double-angle identity for sine The double-angle identity for sine is: sin 2A = 2 sin A cos A. Substitute this into the given equation: 2 sin A cos A = 2 sin A. Step 2: Simplify the equation Divide both sides of the equation by 2 (assumiRead more
We are given the equation:
sin 2A = 2 sin A.
Step 1: Recall the double-angle identity for sine
The double-angle identity for sine is:
sin 2A = 2 sin A cos A.
Substitute this into the given equation:
2 sin A cos A = 2 sin A.
Step 2: Simplify the equation
Divide both sides of the equation by 2 (assuming sin A ≠ 0):
sin A cos A = sin A.
Rearrange the terms:
sin A cos A – sin A = 0.
Factor out sin A:
sin A (cos A – 1) = 0.
Step 3: Solve for A
This equation is satisfied if either:
1. sin A = 0, or
2. cos A – 1 = 0.
Case 1: sin A = 0
The sine function is zero when A = 0°, 180°, etc. Among the given options, A = 0° satisfies this condition.
Case 2: cos A – 1 = 0
Solve for cos A:
cos A = 1.
The cosine function equals 1 when A = 0°, 360°, etc. Again, among the given options, A = 0° satisfies this condition.
Step 4: Verify the solution
Substitute A = 0° into the original equation:
sin 2(0°) = 2 sin(0°).
The left-hand side:
sin 2(0°) = sin 0° = 0.
The right-hand side:
2 sin(0°) = 2(0) = 0.
Since both sides are equal, A = 0° satisfies the equation.
Step 5: Final Answer
The value of A is 0°.
The correct answer is:
a) 0°
This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.
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If 16 cot x = 12, then sin x – cos x/ sin x + cos x equals
We are given: 16 cot x = 12. Step 1: Solve for cot x Rearrange the equation to solve for cot x: cot x = 12/16 = 3/4. Step 2: Express tan x in terms of cot x Using the identity cot x = 1/tan x, we can write: tan x = 1/cot x = 1/(3/4) = 4/3. Step 3: Express sin x and cos x in terms of tan x Using theRead more
We are given:
16 cot x = 12.
Step 1: Solve for cot x
Rearrange the equation to solve for cot x:
cot x = 12/16 = 3/4.
Step 2: Express tan x in terms of cot x
Using the identity cot x = 1/tan x, we can write:
tan x = 1/cot x = 1/(3/4) = 4/3.
Step 3: Express sin x and cos x in terms of tan x
Using the identity tan x = sin x / cos x, we can write:
sin x = 4k and cos x = 3k,
where k is a positive constant such that sin²x + cos²x = 1 (Pythagorean identity).
Substitute sin x = 4k and cos x = 3k into the identity:
(4k)² + (3k)² = 1
16k² + 9k² = 1
25k² = 1
k² = 1/25
k = √(1/25)
k = 1/5.
Thus:
sin x = 4k = 4/5,
cos x = 3k = 3/5.
Step 4: Simplify the given expression
We are tasked with finding the value of:
(sin x – cos x) / (sin x + cos x).
Substitute sin x = 4/5 and cos x = 3/5 into the expression:
Numerator:
sin x – cos x = (4/5) – (3/5)
= (4 – 3)/5
= 1/5.
Denominator:
sin x + cos x = (4/5) + (3/5)
= (4 + 3)/5
= 7/5.
Thus, the entire expression becomes:
(sin x – cos x) / (sin x + cos x) = (1/5) / (7/5).
Simplify:
(1/5) / (7/5) = 1/7.
Step 5: Final Answer
The value of (sin x – cos x) / (sin x + cos x) is 1/7.
The correct answer is:
a) 1/7
This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.
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If angles A, B, C of a Triangle ABC from an increasing Ao, then sin B =
We are given that the angles A, B, and C of a triangle △ABC form an increasing arithmetic progression (AP). We need to find the value of sin B. Step 1: Properties of angles in a triangle The sum of the angles in any triangle is: A + B + C = 180°. Since A, B, and C form an increasing arithmetic progrRead more
We are given that the angles A, B, and C of a triangle △ABC form an increasing arithmetic progression (AP). We need to find the value of sin B.
Step 1: Properties of angles in a triangle
The sum of the angles in any triangle is:
A + B + C = 180°.
Since A, B, and C form an increasing arithmetic progression, let the common difference of the AP be d. Then we can write:
A = B – d, B = B, C = B + d.
Substitute these into the angle sum property:
(B – d) + B + (B + d) = 180°.
Simplify:
3B = 180°.
Solve for B:
B = 60°.
Step 2: Find sin B
Now that we know B = 60°, we use the standard trigonometric value:
sin 60° = √3/2.
Step 3: Final Answer
The value of sin B is:
√3/2.
The correct answer is:
b) √3/2
This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-8/