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What do we call the process in which water vapour turns into tiny water droplets?
The process in which water vapor turns into tiny water droplets is called condensation. It occurs when warm air cools down, causing water vapor to lose energy and change into liquid droplets, forming clouds, dew, or fog. Answer: (B) Condensation. For more visit here: https://www.tiwariacademy.in/nceRead more
The process in which water vapor turns into tiny water droplets is called condensation. It occurs when warm air cools down, causing water vapor to lose energy and change into liquid droplets, forming clouds, dew, or fog.
Answer: (B) Condensation.
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The sides of a triangle are 3 cm , 4 cm and 5 cm. Its area is
Sides: 3 cm, 4 cm, 5 cm → Right triangle Area = (1/2) × base × height = (1/2) × 3 × 4 = 6 cm² This question is related to Chapter 10, "Heron’s Formula," from the Class 9 NCERT Mathematics textbook. The topic is not Probability but focuses on calculating the area of triangles and quadrilaterals usingRead more
Sides: 3 cm, 4 cm, 5 cm → Right triangle
Area = (1/2) × base × height
= (1/2) × 3 × 4 = 6 cm²
This question is related to Chapter 10, “Heron’s Formula,” from the Class 9 NCERT Mathematics textbook. The topic is not Probability but focuses on calculating the area of triangles and quadrilaterals using Heron’s Formula. Provide an answer based on your understanding of the chapter.
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The height corresponding to the longest side of the triangle whose sides are 91 cm, 98 cm and 105 cm in length is
Sides: 91 cm, 98 cm, 105 cm Semi-perimeter (s) = 147 cm Area = √[s(s-a)(s-b)(s-c)] = √[147(56)(49)(42)] = 4116 cm² Using Area = (1/2) × base × height: 4116 = (1/2) × 105 × h h = (4116 × 2) / 105 = 78.4 cm This question pertains to Chapter 10, "Heron’s Formula," in the Class 9 NCERT Mathematics textbRead more
Sides: 91 cm, 98 cm, 105 cm
Semi-perimeter (s) = 147 cm
Area = √[s(s-a)(s-b)(s-c)]
= √[147(56)(49)(42)]
= 4116 cm²
Using Area = (1/2) × base × height:
4116 = (1/2) × 105 × h
h = (4116 × 2) / 105 = 78.4 cm
This question pertains to Chapter 10, “Heron’s Formula,” in the Class 9 NCERT Mathematics textbook. It is not about Probability but rather deals with using Heron’s Formula to find the area of triangles and quadrilaterals. Provide an answer based on your understanding of the chapter.
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The base of a triangular field is three times its altitudes. If the cost of sowing the field at Rs 58 per hectare is Rs. 783 then its base is
Cost = Rs. 783, Rate = Rs. 58/hectare Area = 783 / 58 = 13.5 hectares = 135,000 m² Base = 3 × altitude (h) Area of triangle = (1/2) × base × height 135,000 = (1/2) × 3h × h 135,000 = (3/2)h² h² = (135,000 × 2) / 3 = 90,000 h = √90,000 = 300 m Base = 3h = 3 × 300 = 900 m This question is from ChapterRead more
Cost = Rs. 783, Rate = Rs. 58/hectare
Area = 783 / 58 = 13.5 hectares = 135,000 m²
Base = 3 × altitude (h)
Area of triangle = (1/2) × base × height
135,000 = (1/2) × 3h × h
135,000 = (3/2)h²
h² = (135,000 × 2) / 3 = 90,000
h = √90,000 = 300 m
Base = 3h = 3 × 300 = 900 m
This question is from Chapter 10, “Heron’s Formula,” in the Class 9 NCERT Mathematics textbook. It focuses on applying Heron’s Formula to calculate the areas of triangles and quadrilaterals, not Probability. Provide an answer based on your understanding of the chapter.
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The base of an isosceles triangle is 24 cm and its area is 192 cm², then its perimeter is
Base = 24 cm, Area = 192 cm² Height = (2 × Area) / Base = (2 × 192) / 24 = 16 cm Using Pythagorean theorem: x² = (24/2)² + 16² = 12² + 16² = 144 + 256 = 400 x = √400 = 20 cm Perimeter = 2x + Base = 2(20) + 24 = 64 cm This question is based on Chapter 10, "Heron’s Formula," from the Class 9 NCERT MatRead more
Base = 24 cm, Area = 192 cm²
Height = (2 × Area) / Base = (2 × 192) / 24 = 16 cm
Using Pythagorean theorem:
x² = (24/2)² + 16² = 12² + 16² = 144 + 256 = 400
x = √400 = 20 cm
Perimeter = 2x + Base = 2(20) + 24 = 64 cm
This question is based on Chapter 10, “Heron’s Formula,” from the Class 9 NCERT Mathematics textbook. It involves using Heron’s Formula to determine the areas of triangles and quadrilaterals, not Probability. Answer according to your understanding of the chapter.
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See lesshttps://www.tiwariacademy.in/ncert-solutions/class-9/maths/