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The temperature in the high-altitude desert of Ladakh is recorded as 4 °C at noon. By midnight, it drops by 15 °C. What is the midnight temperature?
The recorded temperature at noon in the high-altitude desert of Ladakh starts at 4 degrees Celsius. To find the new temperature after a drop of 15 degrees Celsius by midnight, we must subtract 15 from the initial value. Setting up the arithmetic expression gives 4 minus 15. Calculating this integerRead more
The recorded temperature at noon in the high-altitude desert of Ladakh starts at 4 degrees Celsius. To find the new temperature after a drop of 15 degrees Celsius by midnight, we must subtract 15 from the initial value. Setting up the arithmetic expression gives 4 minus 15. Calculating this integer operation yields a final value of -11. Therefore, the temperature at midnight is -11 degrees Celsius.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 3 The world of numbers (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-3/
See lessA spice trader takes a loan (debt) of rupees 850. The next day, he makes a profit (fortune) of rupees 1,200. The following week, he incurs a loss of rupees 450. Write this sequence as an equation using integers and calculate his final financial standing.
We can represent financial transactions using signed integers where debts and losses are negative, and profits are positive. The trader starts with a loan of -850 rupees, adds a profit of +1200 rupees, and adds a loss of -450 rupees. The complete sequence forms the integer equation -850 + 1200 - 450Read more
We can represent financial transactions using signed integers where debts and losses are negative, and profits are positive. The trader starts with a loan of -850 rupees, adds a profit of +1200 rupees, and adds a loss of -450 rupees. The complete sequence forms the integer equation -850 + 1200 – 450. Adding the numbers together gives 350 – 450, which equals -100. His final financial standing is a net debt of 100 rupees.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 3 The world of numbers (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-3/
See lessHow is it different from the algebraic expression in Example 1?
The algebraic expression in Example 1 is 4x + 5y + 3, where the variables x and y appear separately in different terms. In Example 2, the expression is 200l + 160w + 50lw. The important difference is that the term 50lw contains two variables multiplied together. Example 1 includes a constant term 3,Read more
The algebraic expression in Example 1 is 4x + 5y + 3, where the variables x and y appear separately in different terms. In Example 2, the expression is 200l + 160w + 50lw. The important difference is that the term 50lw contains two variables multiplied together. Example 1 includes a constant term 3, but Example 2 has no constant term. Also, Example 1 is about counting pens and pencils, while Example 2 is related to the cost of fencing and seeds.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA wire of length 20 cm is bent in different ways to form rectangles. For example, we can have a rectangle with length 7 cm and width 3 cm. We can also have one of length 5.5 cm and width 4.5 cm. (Think of a few more ways of forming such rectangles.) Can you write an expression for the area of such rectangles?
The total length of the wire is 20 cm, so the perimeter of the rectangle is 20 cm. Since the perimeter formula is 2 multiplied by length plus width, the sum of length and width becomes 10 cm. If the length is x cm, then the width will be 10 minus x cm. The area of a rectangle is length multiplied byRead more
The total length of the wire is 20 cm, so the perimeter of the rectangle is 20 cm. Since the perimeter formula is 2 multiplied by length plus width, the sum of length and width becomes 10 cm. If the length is x cm, then the width will be 10 minus x cm. The area of a rectangle is length multiplied by width. Therefore, the expression for the area of the rectangle is x multiplied by 10 minus x or 10x minus x square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessWrite polynomials of degrees 1, 2 and 3.
The degree of a polynomial depends on the highest power of the variable. A polynomial of degree 1 is called a linear polynomial, such as 3x plus 2. A polynomial of degree 2 is called a quadratic polynomial, such as x square plus 5x plus 1. A polynomial of degree 3 is called a cubic polynomial, suchRead more
The degree of a polynomial depends on the highest power of the variable. A polynomial of degree 1 is called a linear polynomial, such as 3x plus 2. A polynomial of degree 2 is called a quadratic polynomial, such as x square plus 5x plus 1. A polynomial of degree 3 is called a cubic polynomial, such as 2x cube minus x plus 4. In each case, the highest power of x determines the degree of the polynomial.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See less