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What should be recorded during a field trip related to dance observation?
While on a field trip focused on dance observation, students are encouraged to record key details like the name of the dance, the performers’ names and what steps, movements and expressions were observed. They should also note the musical instruments used, costumes worn and any unique traditions orRead more
While on a field trip focused on dance observation, students are encouraged to record key details like the name of the dance, the performers’ names and what steps, movements and expressions were observed. They should also note the musical instruments used, costumes worn and any unique traditions or stories shared by the dancers. This documentation supports a deeper reflection on the experience and helps in comparing and understanding different dance forms in later discussions or assignments.
See lessWhich state is Garba dance associated with?
Garba is a traditional dance form that originates from the state of Gujarat in western India. It is an essential part of the state’s cultural identity and is particularly popular during the Navaratri festival, where people perform Garba in colorful attire, forming circles and dancing rhythmically toRead more
Garba is a traditional dance form that originates from the state of Gujarat in western India. It is an essential part of the state’s cultural identity and is particularly popular during the Navaratri festival, where people perform Garba in colorful attire, forming circles and dancing rhythmically to devotional songs. The dance is a joyful expression of devotion and unity, symbolizing celebration and reverence, especially toward the Goddess Durga.
See lessA galvanometer having 20 division scale and 50 Ω resistance is connected in series to a cell of e.m.f. 1.5 V through a resistance of 100 Ω, shows full scale deflection. The figure of merit of the galvanometer in microampere/division is
Total resistance in the circuit = 100Ω + 50Ω = 150Ω Current through the galvanometer at full scale deflection: I = V/R = 1.5/150 = 0.01A = 10, 000µA Galvanometer has 20 divisions, so: Figure of merit = 10, 000µA/20 = 500 μA/division Answer: (C) 500. For more visit here: https://www.tiwariacademy.comRead more
Total resistance in the circuit = 100Ω + 50Ω = 150Ω
Current through the galvanometer at full scale deflection:
I = V/R = 1.5/150 = 0.01A = 10, 000µA
Galvanometer has 20 divisions, so:
Figure of merit = 10, 000µA/20 = 500 μA/division
Answer: (C) 500.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/
A galvanometer of resistance 3663 Ω gives full scale deflection for a certain current Ig. The value of the resistance of the shunt which when joined to the galvanometer coil will result in 1/34 of the total current passing through the galvanometer is
Let the shunt resistance be Rs and galvanometer resistance be Rg = 3663Ω Given: only 1/34 of total current I passes through the galvanometer. Using current division rule: Ig/Is = Rs/Rg ' Where Ig/I = 1/34' ⇒ Is/I = 33/34 So: 1/33 = Rs/3663 ⇒ Rs = 3663/33 = 111 Ω ≈100Ω Answer: (A) 100 Ω.
Let the shunt resistance be
Rs and galvanometer resistance be
Rg = 3663Ω
Given: only 1/34 of total current I passes through the galvanometer.
Using current division rule:
Ig/Is = Rs/Rg ‘ Where Ig/I = 1/34’ ⇒ Is/I = 33/34
So:
1/33 = Rs/3663 ⇒ Rs = 3663/33 = 111 Ω ≈100Ω
Answer: (A) 100 Ω.
See lessA galvanometer with resistance 1000 Ω gives full scale deflection at 0.1 mA. What value of resistance should be added to 1000 Ω to increase its current range 10 A.
To convert the galvanometer into an ammeter reading up to 10 A, a small shunt resistance must be added in parallel, allowing most current to bypass the galvanometer. The galvanometer allows only 0.1 mA. Using the formula Rs = Ig.Rg/I-Ig, we get Rs ≈ 0.01Ω. Correct answer: (B) 0.01 Ω in parallel. ForRead more
To convert the galvanometer into an ammeter reading up to 10 A, a small shunt resistance must be added in parallel, allowing most current to bypass the galvanometer. The galvanometer allows only 0.1 mA. Using the formula Rs = Ig.Rg/I-Ig, we get Rs ≈ 0.01Ω.
Correct answer: (B) 0.01 Ω in parallel.
For more visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/