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  1. The magnetic field due to a long straight current-carrying wire is given by: B = μ0I/2πr Here, B ∝ 1/r . If the distance increases from 5 cm to 20 cm (i.e., four times), the magnetic field decreases by the same factor: B′ = B/4. Therefore, the new magnetic field is B/4. Answer: (B) B/4. For more visRead more

    The magnetic field due to a long straight current-carrying wire is given by:
    B = μ0I/2πr
    Here, B ∝ 1/r .
    If the distance increases from 5 cm to 20 cm (i.e., four times), the magnetic field decreases by the same factor:
    B′ = B/4.
    Therefore, the new magnetic field is B/4.
    Answer: (B) B/4.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/

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  2. Magnetic induction at the center of a single-turn circular loop carrying current I is given by: B = μ0​I/2​R When the wire is looped into two turns, the number of turns n = 2 and the magnetic induction becomes: B' = n² B = 2²B = 4B Thus, the new magnetic induction at the center is 4B. Answer: (C) 4BRead more

    Magnetic induction at the center of a single-turn circular loop carrying current I is given by:
    B = μ0​I/2​R
    When the wire is looped into two turns, the number of turns
    n = 2 and the magnetic induction becomes:
    B’ = n² B = 2²B = 4B
    Thus, the new magnetic induction at the center is 4B.
    Answer: (C) 4B.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/

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  3. The magnetic force per unit length between two parallel currents is given by: F/L = μ0​I₁ I₂/2πd Here, I₁​ = 10 A, I₂ = 2 A, d = 0.1 m: Substituting values: F/L = (4π ×10⁻⁷) (10) (2)/2π (0.1) = 4 × 10⁻⁵ N/m For 2 m length of wire B, the total force is: F = 4 × 10⁻⁵ × 2 = 8 × 10⁻⁵ N Answer: (A) 8 × 1Read more

    The magnetic force per unit length between two parallel currents is given by:
    F/L = μ0​I₁ I₂/2πd
    Here, I₁​ = 10 A, I₂ = 2 A, d = 0.1 m: Substituting values:
    F/L = (4π ×10⁻⁷)
    (10) (2)/2π (0.1) = 4 × 10⁻⁵ N/m
    For 2 m length of wire B, the total force is:
    F = 4 × 10⁻⁵ × 2 = 8 × 10⁻⁵ N
    Answer: (A) 8 × 10⁻⁵ N.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/

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  4. During the Bhakti movement, dance played a crucial role in spreading moral values by portraying spiritual narratives and ethical lessons. It used expressive gestures, rhythmic movements and devotional themes to convey messages of love, faith and righteousness. Dance performances in temples and publiRead more

    During the Bhakti movement, dance played a crucial role in spreading moral values by portraying spiritual narratives and ethical lessons. It used expressive gestures, rhythmic movements and devotional themes to convey messages of love, faith and righteousness. Dance performances in temples and public gatherings reinforced virtues like humility, devotion and selflessness, making religious teachings accessible to all. By engaging audiences emotionally and visually, dance became a powerful medium to promote ethical living and strengthen communal faith.

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  5. Allowing both boys and girls to practice Lavani and Bhangra encourages gender inclusivity in dance. It breaks stereotypes by showcasing that dance is for everyone, regardless of tradition or physicality. Lavani, traditionally performed by women, teaches grace and expressiveness, while Bhangra, knownRead more

    Allowing both boys and girls to practice Lavani and Bhangra encourages gender inclusivity in dance. It breaks stereotypes by showcasing that dance is for everyone, regardless of tradition or physicality. Lavani, traditionally performed by women, teaches grace and expressiveness, while Bhangra, known for its energy, builds stamina and coordination. Learning these dances fosters cultural appreciation, self-confidence and teamwork. It ensures that traditional dance forms evolve, becoming more accessible and widely practiced across genders and generations.

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