Varnu Singh
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In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.

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NCERT Solutions for Class 8 Mathematics Chapter 8
Important NCERT Questions
Comparing Quantities Chapter 8 Exercise 8.3
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 11

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1 Answer

  1. Here, Principal (P) = 5,06,000, Rate of Interest (R) = 2.5%, Time (n) = 2 hours
    After 2 hours, number of bacteria,
    Amount (A) =P(1+R/100)ⁿ
    = 506000(1+ 2.5/100)²
    = 506000(1+ 25/100)²
    = 506000(1+ 25/40)²
    = 506000(41/40)²
    = 506000 x 41/40 x 41/40 = 5,31,616.25
    Hence, number of bacteria after two hours are 531616 (approx.).

    Class 8 Maths Chapter 8 Exercise 8.3 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-8/

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