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Ashok0210
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Asked: 2021-02-23T03:56:48+00:00 In:

What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30º with the direction of a uniform magnetic field of 0.15 T?

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Class 12 Physics
CBSE and UP Board
Moving Charges and Magnetism
Chapter-4 Exercise 4.5

2020-2021cbse and up boardclass 12 chapter-4 physicsclass 12 physicsncert class 12 moving charges and magnetism
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    1 Answer

    1. Current in the wire, I = 8 A

      Magnitude of the uniform magnetic field, B = 0.15 T

      Angle between the wire and magnetic field, 0 = 30°. Magnetic force per unit length on the wire is given as: f = BI sin0 = 0.15 x 8 x 1 x Sin30° = 0.6 N m1

      Hence, the magnetic force per unit length on the wire is 0.6 N m⁻1.

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