NCERT Solutions for Class 11 Science Kinematic 2
Important Board Questions
Kinematic
NCERT Books for Session 2022-2023
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Numericals Marks Questions
A cyclist is riding with a speed of 27 kmh⁻¹ . As he approaches a circular turn on the road of radius 30 m, he applies brakes and reduces his speed at the constant rate 0.5 ms⁻²). What is the magnitude and direction of the net acceleration of the cyclist on the circular turn ?
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ac = V ² = 0.7 ms⁻²
aₜ = 0.5 ms⁻²
a = √(2^2 c+a²)ₜ=0.86⁻²
If θ is the angle between the net acceleration and the velocity of the cyclist,
then
θ = tan⁻¹(ac+ aₜ) = tan(_^(-1)) (1.4) =54°28′