Ravi Kishan Verma
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Poll

A straight conducting rod of length l and mass is suspended in a horizontal plane by a pair of flexible strings in a magnetic field of magnitude B. To remove the tension in the supporting strings, the magnitude of current in the wire is :

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Poll Results

0%(A) mgB/l
0%(B) mgl/B
80%(C) mg/lB ( 4 voters )
20%(D) lB/mg ( 1 voter )
Based On 5 Votes

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To remove the tension in the supporting strings, the magnetic force (BIl) should balance the gravitational force (mg). Therefore, equating BIl = mg, the current required is I = mg/Bl. Hence, the Correct answer is (c) mg/lB.

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1 Answer

  1. To remove tension in the strings, the magnetic force must balance the gravitational force:
    Bil = mg
    Rearranging for current I:
    I = mg/BL
    Thus, the magnitude of current needed to make the net force zero is:
    I = mg/BL
    Answer: (C) mg/IB

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-4/

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