The value of the gravitational constant G was first determined experimentally by English scientist Henry Cavendish in 1798.
NCERT Class 11 Physics
Gravitation
CBSE EXAM 2024-25
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In 1798, the English scientist Henry Cavendish experimentally determined the value of the gravitational constant ๐บ. The apparatus used is depicted in the figure. It consists of two small identical lead spheres, each of mass ๐, attached to the ends of a lightweight rod, forming a dumbbell. This rod is suspended vertically by a thin fiber. Two larger lead spheres, each of mass ๐, are placed near the smaller spheres, ensuring all four spheres lie in a horizontal plane. The small spheres are attracted to the larger spheres by the gravitational force, given by:F = G Mm/rยฒ
where ๐ is the distance between the centers of a large sphere and its neighboring small sphere.
Torque and Equilibrium:
The forces on the two small spheres form a couple that exerts a torque on the dumbbell. This torque causes the rod to rotate and twist the suspension fiber until the restoring torque of the fiber balances the gravitational torque. The angle of deflection (๐) is measured using a lamp and scale arrangement, which detects the deflection of a light beam.
Deflecting Torque: tau_deflecting = F . L = G Mm/rยฒ . L,
where ๐ฟ is the length of the rod.
Restoring Torque:
tau_restoring = k๐,
where ๐ is the torsion constant of the fiber (restoring torque per unit angle of twist).
In rotational equilibrium, the two torques are equal and opposite:
G Mm/rยฒ . L = k๐,
Rearranging, the value of ๐บ is:
๐บ = k๐rยฒ / MmL
Determination of ๐บ
By measuring all the quantities on the right-hand side during the experiment, the value of ๐บ can be calculated. Cavendish’s experiment laid the foundation for precise determination of
๐บ, and modern methods have refined its measurement. The currently accepted value is:
G = 6.67 ร 10โปยนยน Nmยฒ kgโปยฒ.