NCERT Solutions for Class 9 Science Chapter 9
Force and Laws of Motion
NCERT Books for Session 2022-2023
CBSE Board and UP Board
Intext Questions
Page No-126
Questions No-4
Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 m s–1 and 1 m s–1, respectively. They collide and after the collision, the first object moves at a velocity of 1.67 m s–1. Determine the velocity of the second object.
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Mass of one of the objects, m₁ = 100 g = 0.1 kg
Mass of the other object, m₂ = 200 g = 0.2 kg Velocity of m1 before collision, v₁ = 2 m/s
Velocity of m2 before collision, v₂ = 1 m/s
Velocity of m1 after collision, v₄ = 1.67 m/s
Velocity of m2 after collision = v₄
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄
⇒ 0.1×2 + 0.2×1 = 0.1×1.67 + 0.2×v₄
⇒ 0.4 = 0.67 + 0.2×v₄
⇒ v₄ = 1.165 m/s
Hence, the velocity of the second object becomes 1.165 m/s after the collision.
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