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Home/ Questions/Q 627
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Ankur Bansal
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Ankur Bansal
Asked: October 18, 20202020-10-18T09:10:45+00:00 2020-10-18T09:10:45+00:00In: Class 10

Why is the amount of gas collected in one of the test tubes in Activity 1.7 double of the amount collected in the other? Name this gas.

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NCERT Solution for Class 10 Science Chapter 1
Chemical Reactions and Equations
Intext Questions
Page No-10
Questions No-2

Why is the amount of gas collected in one of the test tubes in Activity
1.7 double of the amount collected in the other? Name this gas.

cbseclass10ncertscience
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    1. Uchit
      2020-12-05T06:13:10+00:00Added an answer on December 5, 2020 at 6:13 am

      During the Electrolysis of water, hydrogen and oxygen is get separated by the electricity. Water (H2O) contains two parts hydrogen and one part oxygen. Since hydrogen goes to one test tube and oxygen goes to another, the amount of gas collected in one of the test tubes is double of the amount collected in the other.

      For more answers visit to website:
      https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-1/

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    2. R k Parsad
      2023-11-30T12:13:33+00:00Added an answer on November 30, 2023 at 12:13 pm

      To provide a more accurate response, I would need additional details about “Activity 1.7” and the gases involved. However, I can offer a general explanation for why the amount of gas collected in one test tube might be double that of another.

      If the activity involves the reaction of a metal with an acid, such as zinc with hydrochloric acid, the balanced chemical equation for the reaction is:

      Zn + 2HCl → ZnCl₂ + H₂

      In this reaction, one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas. This means that the amount of hydrogen gas generated is directly proportional to the amount of zinc used.

      If one test tube has twice the amount of zinc compared to the other, the amount of hydrogen gas collected in that test tube would be double because the reaction involves a 1:2 ratio of zinc to hydrogen gas.

      It’s important to note that this explanation assumes the context of a specific experimental setup. If your activity involves a different reaction or set of conditions, please provide more details for a more accurate response.

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