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When a solid body is immersed in water, its weight decreases. How much is this loss?

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Poll Results

50%[A] Equal to the weight of displaced water ( 1 voter )
0%[B] Less than the weight of displaced water
50%[C] More than the weight of displaced water ( 1 voter )
0%[D] Not related to the weight of displaced water
Based On 2 Votes

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When a solid body is immersed in water, its weight decreases. This loss is equal to the weight of displaced water. According to Archimedes’ principle, the buoyant force acting on the body is equal to the weight of the displaced fluid, resulting in the observed weight loss.

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1 Answer

  1. When a solid body is immersed in water, its weight decreases. This loss is equal to the weight of displaced water (A). Archimedes’ principle states that the buoyant force acting on a submerged object is equal to the weight of the displaced fluid. Therefore, the weight loss of the solid body when immersed in water is precisely equal to the weight of the water it displaces. This principle applies regardless of the shape or material of the submerged object. Options (B), (C), and (D) are incorrect because they do not align with Archimedes’ principle, which clearly establishes the relationship between the weight loss of a submerged object and the weight of the displaced water. Therefore, the correct option is (A) Equal to the weight of displaced water.

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