Class 12 Physics
CBSE and UP Board
Electromagnetic Waves
Chapter-8 Exercise 8.13
NCERT Solutions for Class 12 Physics Chapter 8 Question 13
Additional Exercise
Use the formula λm T= 0.29 cm K to obtain the characteristic temperature ranges for different parts of the electromagnetic spectrum. What do the numbers that you obtain tell you?
Share
A body at a particular temperature produces a continuous spectrum of wavelengths. In case of a black body, the wavelength corresponding to maximum intensity of radiation is given according to Planck’s law. It can be given by the relation,
λm= 0.29/T cm K
Where,
λm= maximum wavelength and T = temperature.
Thus, the temperature for different wavelengths can be obtained as:
For λm = 10⁻4 cm; T = 0.29/10⁻4 = 2900 °K
For λm = 5 x 10⁻5 cm; T = 0.29/(5 x 10⁻5) = 5800 °K
For λm = 10⁻⁶ cm; T = 0.29/( 10⁻⁶) = 290000 °K and so on.
The numbers obtained tell us that temperature ranges are required for obtaining radiations in different parts of an electromagnetic spectrum. As the wavelength decreases, the corresponding temperature increases.