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Two wires A and B of the same material having length in the ratio 1 : 2 and diameter in the ratio 2 : 3 are connected in series with a battery. The ratio of potential differences (Va/Vb) across the two wires respectively is
Resistance is given by R = p L/A . Given La/Lb = 1/2 and da/db = 2/3, so Aa/Ab = 2/3 2 = 4/g. thus, Ra/Rb = (1/2)/(4g) = 9/8. Since V ∝ R in series,
Va/Vb = Ra/Rb = 9/8
Answer: (d) 9/8.
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NCERT Solutions for Class 12 Physics Chapter 3 Current Electricity
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