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Two water taps together can fill a tank in 9(3/8) hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

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Important Quadratic Equations related Questions.
Diameter based quadratic equations questions are a type of mathematical problem that involve using the concept of diameter, flow rate and time to fill a tank.
NCERT Solutions for Class 10th Maths.
EXERCISE 4.3 Questions No:9

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1 Answer

  1. Let, the time taken by large tap to fill the tank = x hours
    So, the time taken by smaller tap to fill the tank = x + 10 hours
    Therefore, in 1 hour,
    tank filled by larger tap = 1/x+10
    According to question,
    1/x + 1/x + 10 = 1/(9 (3/8))

    ⇒ x + 10 + x/x(x + 10) = 8/75
    ⇒ 75(2x + 10) = 8x(x + 10)
    ⇒ 150x +750 = 8x² + 80x
    ⇒ 8x² – 70x – 750 = 0
    ⇒ 4x² – 35x – 375 = 0
    ⇒ 4x² – 60x + 25x – 375 = 0
    ⇒ 4x(x – 15) + 25 (x – 15) = 0
    ⇒ (x – 15) (x + 25) = 0
    ⇒ (x – 15) = 0 or (x + 25) = 0
    Either x = 15 or x = – 25
    But, x ≠ – 25, as x is the time taken to fill the tank which can’t be negative. So, x
    Hence, the time taken by larger top to fill the tank = 15 hours
    and the time by smaller tap to fill the tank = 15 + 10 = 25 hours.

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