Half of the chords are 5 cm and 12 cm. Let the distance of the 24 cm chord from the centre be x. Then the other is x + 7. Solving gives x = 5 and radius = 13 cm.
Two parallel chords of lengths 10 cm and 24 cm are on the same side of the centre of a circle. The distance between the chords is 7 cm. Find the radius of the circle.
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The half-lengths of the chords are 5 cm and 12 cm. Since the longer chord is closer to the centre, let its distance from the centre be x. Then the distance of the 10 cm chord is x + 7.
Using right triangles:
r² = x² + 12²
r² = (x + 7)² + 5²
Therefore,
x² + 144 = x² + 14x + 49 + 25
14x = 70
x = 5
Thus, r² = 25 + 144 = 169, so r = 13 cm.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/