The total taxi fare consists of fixed charge x plus distance charge. Sahil’s 6 km journey gives x + 6y = 122, while Meena’s 8 km journey gives x + 8y = 160.
class 9 maths ganita manjari part 2 chapter 13 question answer
Ganita Manjari Part 2 chapter 13 Two Variables, One Line solutions
With a fixed base charge of ₹x and a running charge of ₹y per kilometre, the total fare equals x + (distance × y). For Sahil, travelling 6 km at a total cost of ₹122 leads to x + 6y = 122. For Meena, travelling 8 km with a total fare of ₹160 produces x + 8y = 160. These two relations construct the required system.
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