The total number of terms in the expansion of (a³ -3a²b + 3ab² – b³)⁵⁰ is:
The Binomial Theorem, covered in Class 11 Chapter 7 of the CBSE 2024-2025 NCERT Maths syllabus, explains how to expand binomial expressions efficiently. This chapter introduces fundamental concepts such as binomial coefficients, Pascal’s Triangle and the general formula for expansion. It also explores real-world applications, making complex algebraic expressions easier to simplify. To help students assess their grasp of the topic, the chapter includes MCQ questions that strengthen problem-solving abilities and boost preparation for board exams and competitive tests. By mastering the Binomial Theorem, students develop a solid mathematical foundation while improving logical reasoning. Understanding this topic not only enhances algebraic skills but also lays the groundwork for higher-level mathematics and advanced calculations.
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Choice (a) is correct.
We have, (a³ -3a²b + 3ab² – b³)⁵⁰ = {(a – b)³}⁵⁰ = (a – b)¹⁵⁰
We know that the total number of terms in the expansion of (x + a)ⁿ is (n + 1).
Total number of terms in the expansion of (a – b)¹⁵⁰ is (150 + 1) = 151.
Total number of terms in the expansion of (a³ – 3a²b + 3ab² – b³)⁵⁰ is 151.
This question related to Chapter 7 maths Class 11th NCERT. From the Chapter 7: Binomial Theorem. Give answer according to your understanding.
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