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Piyush365
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Asked: 2026-09-30T11:23:08+00:00 In:

The surface areas of the three faces of a cuboid that meet at one of the corners of the cuboid are 6 cm², 15 cm² and 10 cm² respectively. What is the volume of the cuboid?

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Let the dimensions be l, w, and h. The product of the three adjacent face areas equals (lwh)², which is 6 × 15 × 10 = 900. Taking the square root gives a volume of 30 cm³.

Ganita Manjari part 2 Chapter 14.1 Solutions
Class 9 Ganita Manjari Part 2 Chapter 14 Page 126 Question Answer

cbse class 9 maths ganita manjari part 2 solutionsclass 9 maths ganita manjari part 2 chapter 14 question answerganita manjari part 2 chapter 14 math of space surface area and volume solutionssurface areas of the three faces of a cuboidvolume of the cuboid
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    1. Let the length, width and height of the cuboid be l, w and h respectively. The areas of the three adjacent faces meeting at a corner are lw = 6, wh = 15 and hl = 10. Multiplying these equations yields (lwh)² = 6 × 15 × 10 = 900. Since volume V equals lwh, taking the square root gives V = √900 = 30 cm³.

       

      For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/

       

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