Sphere surface area = 4π(5)² = 100π cm². Since this is five times the cone CSA, cone CSA = 20π cm². Thus, π(4)l = 20π, giving l = 5 cm. Cone height is 3 cm and volume is 16π cm³.
Cbse Class 9 Maths Ganita Manjari Part 2 Solutions
Class 9 maths ganita manjari part 2 chapter 14 question answer
Surface area of the sphere is 4π(5)² = 100π cm². Curved surface area of the cone is πrl = 4πl. Given 100π = 5(4πl), we get l = 5 cm. Using l² = r² + h², h² = 25 − 16 = 9, so h = 3 cm. Hence, cone volume is (1/3)π(4)²(3) = 16π cm³.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/